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2 years ago

Find the area of ABC

Mathematics

2 answers:

Leona [35]2 years ago

7 0

Answer:

area of ABC=1/2 b×h=1/2×20×6=30m²

Elina [12.6K]2 years ago

7 0

Answer:

60 m^2

Step-by-step explanation:

( Base * Hight / 2 = Area)

20 * 6 = 120

120 / 2 = 60

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Which term completes the product so that it is the difference of squares? (-5x-3)(-5x+ )

lilavasa [31]

Hello,

(-5x-3)(-5x+ 3) = (-5x)² - 3²

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2 years ago

What is the answer to 1-2x=-3x+2

scZoUnD [109]

Answer:

x=1

Step-by-step explanation:

1-2x=-3x+2

-1=-x

1=x

8 0

2 years ago

Read 2 more answers

In Triangle XYZ, measure of angle X = 49° , XY = 18°, and

marissa [1.9K]

Answer:

There are two choices for angle Y: $Y \approx 54.987^{\circ}$ for $XZ \approx 15.193$ , $Y \approx 27.008^{\circ}$ for $XZ \approx 8.424$ .

Step-by-step explanation:

There are mistakes in the statement, correct form is now described:

In triangle XYZ, measure of angle X = 49°, XY = 18 and YZ = 14. Find the measure of angle Y:

The line segment XY is opposite to angle Z and the line segment YZ is opposite to angle X. We can determine the length of the line segment XZ by the Law of Cosine:

$YZ^{2} = XZ^{2} + XY^{2} -2\cdot XY\cdot XZ \cdot \cos X$ (1)

If we know that $X = 49^{\circ}$ , $XY = 18$ and $YZ = 14$ , then we have the following second order polynomial:

$14^{2} = XZ^{2} + 18^{2} - 2\cdot (18)\cdot XZ\cdot \cos 49^{\circ}$

$XZ^{2}-23.618\cdot XZ +128 = 0$ (2)

By the Quadratic Formula we have the following result:

$XZ \approx 15.193\,\lor\,XZ \approx 8.424$

There are two possible triangles, we can determine the value of angle Y for each by the Law of Cosine again:

$XZ^{2} = XY^{2} + YZ^{2} - 2\cdot XY \cdot YZ \cdot \cos Y$

$\cos Y = \frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ}$

$Y = \cos ^{-1}\left(\frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ} \right)$

1) $XZ \approx 15.193$

$Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-15.193^{2}}{2\cdot (18)\cdot (14)} \right]$

$Y \approx 54.987^{\circ}$

2) $XZ \approx 8.424$

$Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-8.424^{2}}{2\cdot (18)\cdot (14)} \right]$

$Y \approx 27.008^{\circ}$

There are two choices for angle Y: $Y \approx 54.987^{\circ}$ for $XZ \approx 15.193$ , $Y \approx 27.008^{\circ}$ for $XZ \approx 8.424$ .

6 0

2 years ago

a container of candy is shaped like a cylinder and has a volume of 125.6 cubic centimeters. If the heights of the container is 1

Elenna [48]

The radius of the container is 2 centimeter

<h3>Solution:</h3>

Given that a container of candy is shaped like a cylinder

Given that volume = 125.6 cubic centimeters

Height of conatiner = 10 centimeter

To find: radius of the container

We can use volume of cylinder formula and obatin the radius value

The volume of cylinder is given as:

$\text {volume of cylinder }=\pi r^{2} h$

Where "r" is the radius of cylinder

"h" is the height of cylinder and $\pi$ is constant has value 3.14

Substituting the values in formula, we get

$\begin{array}{l}{125.6=3.14 \times r^{2} \times 10} \\\\ {r^{2}=\frac{125.6}{31.4}} \\\\ {r^{2}=4}\end{array}$

Taking square root on both sides,

$r = \sqrt{4}\\\\r = 2$

Thus the radius of the container is 2 centimeter

4 0

2 years ago

Dan drew the line of best fit on the scatter plot shown below: A graph is shown with scale along x axis from 0 to 10 at incremen

Anit [1.1K]

0, 3
- 10, 15
= -10, -12
therefore, the slope is 6/5, and the intercept (c) is as supplied, 3.
the equation, y=mx+c or y = a + bx, can be applied here where m or b = 6/5, and a or c = 3.

therefore the equation is y=6/5x+3.

To test this, you can put in y = 10(6/5)+3, which spits out y = 15. This way we know it *should* work.

3 0

2 years ago

Find the area of ABC​

Find the area of ABC