<em>Hey</em><em>!</em><em>!</em>
<em>1</em><em> </em><em>and </em><em>2</em><em> </em><em>are</em><em> </em><em>vertical</em><em> </em><em>angles</em><em>.</em>
<em>Vertically</em><em> </em><em>opp</em><em>osite</em><em> </em><em>angles</em><em> </em><em>are</em><em> </em><em>always</em><em> </em><em>equal</em><em> </em><em>to</em><em> </em><em>each</em><em> </em><em>other</em><em>.</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em><em>.</em>
Answer:
1.83% probability there are no car accidents on that stretch on Monday
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given time interval.
The number of accidents on a certain section of I-40 averages 4 accidents per weekday independent across weekdays.
This means that 
What is the probability there are no car accidents on that stretch on Monday?
This is P(X = 0).


1.83% probability there are no car accidents on that stretch on Monday
2.0e-6
Is the answer to your question
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Answer:
y=0.5x+3
Step-by-step explanation: