All categories

3 years ago

PLEASE HELP ASAP! QUESTION IS IN THE PICTURE! 30 POINTS!

Mathematics

1 answer:

Vadim26 [7]3 years ago

5 0

65 = 12.1+h the flower is 65 inches. it has grown 12.1 inches since the last time he measured it. the last time he measured it, it was height h.

65 = 12.1 + h

subtract 12.1 from both sides

65-12.1 = 12.1 + h- 12.1

52.9 = h

The last time he measured it it was 52.9 inches

You might be interested in

If my home is 15 ft in length and 20 ft in width what is my house’s height?

pogonyaev

Answer: What grade work this is? Ima help you.

.Step-by-step explanation:

4 0

3 years ago

Please help, thanks!<br><br> Factor completely<br><br> Sx²- 13x² + 15x²

Andru [333]

Answer:

x^2(S+2)

Step-by-step explanation:

7 0

3 years ago

The length of a rectangle is 25

Flauer [41]

The width is 35in, the length is 95in

7 0

3 years ago

Carpeting costs $20 per square yard. You carpet a room that has a width of 15 feet for $800. What is the length of the room in f

mixer [17]

800/$20 per square yard= 40 sq yards
15ft=5 yards
40 sq yds/5 yards= 8 yards or 24 feet
length= 24 feet or 8 yards

3 0

3 years ago

An airplane travels 6111 kilometers against the wind in 9 hours and 7911 kilometers with the wind in the same amount of time. Wh

natima [27]

Answer:

Speed of the plane in still air: $779\; {\rm km \cdot h^{-1}}$ .

Windspeed: $100\; {\rm km \cdot h^{-1}}$ .

Step-by-step explanation:

Assume that $x\; {\rm km \cdot h^{-1}}$ is the speed of the plane in still air, and that $y\; {\rm km \cdot h^{-1}}$ is the speed of the wind.

When the plane is travelling against wind, the ground speed of this plane (speed of the plane relative to the ground) would be $(x - y)\; {\rm km \cdot h^{-1}}$ .
When this plane is travelling in the same direction as the wind, the ground speed of this plane would be $(x + y)\; {\rm km \cdot h^{-1}}$ .

The question states that when going against the wind ( $v = (x - y)\; {\rm km \cdot h^{-1}}$ ,) the plane travels $6111\; {\rm km}$ in $9\; {\rm h}$ . Hence, $9\, (x - y) = 6111$ .

Similarly, since the plane travels $7911\; {\rm km}$ in $9\; {\rm h}$ when travelling in the same direction as the wind ( $v = (x + y)\; {\rm km \cdot h^{-1}}$ ,) $9\, (x + y) = 7911$ .

Add the two equations to eliminate $y$ . Subtract the second equation from the first to eliminate $x$ . Solve this system of equations for $x$ and $y$ : $x = 779$ and $y = 100$ .

Hence, the speed of this plane in still air would be $779\; {\rm km \cdot h^{-1}}$ , whereas the speed of the wind would be $100\; {\rm km \cdot h^{-1}}$ .

3 0

2 years ago