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3 years ago

Pls help me I would appreciate it be I’m failing:(

Mathematics

2 answers:

Harrizon [31]3 years ago

8 0

I don’t have any paper near me but on ur graph paper start at the point (1,2) and go up 1 and to the right 3 and make a point. Then go back to point (1.2) and go down 1 and to the left 3. Make a point there and draw a line and u have a graph! Hopefully this helps!

kupik [55]3 years ago

6 0

Answer:

plot a point at (1,2) move your pencil up one and right 3 and put a point. repeat until you get a long enough line

Step-by-step explanation:

You might have already finished this but good luck!

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Ryan, a baker, measured the weights of cakes baked in each batch at his bakery and found that the mean weight of each cake is 50

denpristay [2]

Answer: Rejecting the mean weight of each cake as 500 gram when H subscript 0 equals 500

Step-by-step explanation:

Given that :

Null hypothesis : H0 =500

Alternative hypothesis : Ha < 500

Type 1 Error: Type 1 error simply occurs when we reject the Null hypothesis when the Null is true. Alternatively, type 11 error occurs when we fail to reject a false null hypothesis.

Hence, in the scenario above, a type 1 error will occur when we reject the mean weight as 500 even though the Null hypothesis is True.

6 0

4 years ago

What is the difference between the ratio 12 to 18 and the ratio 18 to 12

yanalaym [24]

The numbers are in different orders so that makes both ratios completely different.

7 0

4 years ago

Solve |3x - 4| = 6 a) {-10/3,10/3} b) {-2/3,10/3} c) {-2/3,2/3}

ella [17]

To dea with absolute values you need to apply the definition of absloute value OR get rid of it by squaring both sides of the equality.
Let's try it by using the definition of the absolute value:
$\left | \alpha \right | \left \{ {{ \alpha , \alpha \geq 0} \atop {- \alpha , \alpha \ \textless \ 0}} \right.$

So, having that in mind, we must split the initial equation into two.
$\left | 3x-4 \right | \left \{ {{(3x-4), x \geq 4/3} \atop {-(3x-4),x\ \textless \ 4/3}} \right.$
Then, we end up with two equations:
$3x-4=6 \\ -(3x-4)=6$
Both yield the solutions:
$x=10/3 \\ x= -2/3$

So your answer would be the second option

8 0

3 years ago

Is there another way to put. n --- 8

Varvara68 [4.7K]

I think that if you use a fraction like this n/8

5 0

3 years ago

PLZ HELP! dont just answer something random for points:)tysm

sergiy2304 [10]

Answer:

$4(x^{2} -4)^{2} -76$

Step-by-step explanation:

Take out 4:

4(x^2-8x)-12

=4(x^2-8x+16-16)-12

=4(x^2-8x+16)-64-12

=4(x^2-4)^2 - 76

= $4(x^{2} -4)^{2} -76$

6 0

3 years ago