If randy earns $12.74 per hour, what is his overtime rate? How much should randy make if he works 45 1/2 hours during 1 week?

Mathematics

1 answer:

elena-14-01-66 [18.8K]3 years ago

8 0

Answer:

$19.24 is the overtime rate $579.67 one week

Step-by-step explanation:

So $13.00 its $19.50 so I subtracted $12.74 to $13.00 got 0.26 then subtracted $19.50 by 0.26 and got $19.24

$12.74 times 45.5 that will be $579.67 for just one week

If I didn't get it right. Tell me in the comments. I think I got it right.

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Find the roots of h(t) = (139kt)^2 − 69t + 80

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The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :