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Semmy [17]
3 years ago
9

What is the answer to this question above?

Mathematics
2 answers:
djyliett [7]3 years ago
7 0

Answer:

is it multiple choice

Step-by-step explanation:

kotegsom [21]3 years ago
6 0

Answer:

x is 10 y is 5.8

Step-by-step explanation:

x=y+4.2=10

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The Hydro water department has a monthly service charge of $13.90 and a volume charge of $1.45 for every 100 cubic feet of water
erik [133]

Answer: A

Step-by-step explanation:

In this question, you can disregard the initial $13.90 cost because we're only looking for an INCREASE in price. If the Johnson family used 200 cubic feet MORE of water, we need to multiply 2 * 1.45 which gets us 2.90. We multiply 2 by 1.45 because 200 represented in x is 2, since x is represented in hundreds.

7 0
4 years ago
Altogether, Tim, Laura, and Eric worked 210 hours campaigning for their friend Jake who was running for the senate. Laura worked
Gekata [30.6K]

Let \:  x  \: be  \: the  \: time  \: which \:  Laura \:  worked \\  The \:  time  \: Tim  \: worked:x - 10 \\ The  \: time \:  Eric \:  worked:2x \\ We \:  have  \: an \:  equation:x + x - 10 + 2x = 210 \\  <   =  > 4x = 220 \\  <  =  > x = 55 \: (hrs) \\ So \:  Laura  \: worked  \: for  \: 55 \:  hours  \: on \:  the  \: campaign.

3 0
4 years ago
(-5q squared p) cubed
EleoNora [17]

(-5q^{2} p)^3\\-125q^6p^3

Final answer: -125p^3q^6

7 0
4 years ago
Read 2 more answers
Solve using elimination<br> x+y-2z=8<br> 5x-3y+z=-6<br> -2x-y+4z=-13
Free_Kalibri [48]
So here is your answer with LaTeX issued format interpretation. Full process elucidated briefly, below:

\begin{alignedat}{3}x + y - 2z = 8 \\ 5x - 3y + 2 = - 6 \\ - 2x - y + 4z = - 13 \end{alignedat}

For this equation to get obtained under the impression of those variables we have to eliminate them individually for moving further and simplifying the linear equation with three variables along the axis.

Multiply the equation of x + y - 2z = 8 by a number with a value of 5; Here this becomes; 5x + 5y - 10z = 40; So:

\begin{alignedat}{3}5x + 5y - 10z = 40 \\ 5x - 3y + z = - 6 \\ - 2x - y + 4z = - 13 \end{alignedat}

Pair up the equations in a way to eliminate the provided variable on our side, that is; "x":

5x - 3y + z = - 6

-

5x + 5y - 10z = 40
______________

- 8y + 11z = - 46

Therefore, we are getting.

\begin{alignedat}{3}5x + 5y - 10z = 40 \\ - 8y + 11z = - 46 \\ - 2x - y + 4z = - 13 \end{alignedat}

Multiply the equation of 5x + 5y - 10z = - 40 by a number with a value of 2; Here this becomes; 10x + 10y - 20z = 80.

Multiply the equation of - 2x - y + 4z = - 13 by a number with a value of 5; Here this becomes; - 10x - 5y + 20z = - 65; So:

\begin{alignedat}{3}10x + 10y - 20z = 80 \\ - 8y + 11z = - 46 \\ - 10x - 5y + 20z = - 65 \end{alignedat}

Pair up the equations in a way to eliminate the provided variables on our side, that is; "x" and "z":

- 10x - 5y + 20z = - 65

+
10x + 10y - 20z = 80
__________________

5y = 15

\begin{alignedat}{3}10x + 10y - 20z = 80 \\ - 8y + 11z = - 46 \\ 5y = 15 \end{alignedat}

Multiply the equation of - 8y + 11z = - 46 by a number with a value of 5; Here this becomes; - 40y + 55z = - 230.

Multiply the equation of 5y = 15 by a number with a value of 8; Here this becomes; 40y = 120; So:

\begin{alignedat}{3}10x + 10y - 20z = 80 \\ - 40y + 55z = - 690 \\ 40y = 120 \end{alignedat}

Pair up the equations in a way to eliminate the provided variables on our side, that is; "y":

40y = 120

+

- 40y + 55z = - 230
_________________

55z = - 110

\begin{alignedat}{3}10x + 10y - 20z = 80 \\ - 40y + 55z = - 230 \\ 55z = - 110 \end{alignedat}

Solving for the variable of 'z':

\mathsf{55z = - 110}

\bf{\dfrac{55z}{55} = \dfrac{-110}{55}}

Cancel out the common factor acquired on the numerator and denominator, that is, "55":

z = - \dfrac{\overbrace{\sout{110}}^{2}}{\underbrace{\sout{55}}_{1}}

\boxed{\mathbf{z = - 2}}

Solving for variable "y":

\mathbf{\therefore \quad - 40y - 55 \big(- 2 \big) = - 230}

\mathbf{- 40y - 55 \times 2 = - 230}

\mathbf{- 40y - 110 = - 230}

\mathbf{- 40y - 110 + 110 = - 230 + 110}

Adding the numbered value as 110 into this equation (in previous step).

\mathbf{- 40y = - 120}

Divide by - 40.

\mathbf{\dfrac{- 40y}{- 40} = \dfrac{- 120}{- 40}}

\mathbf{y = \dfrac{- 120}{- 40}}

\boxed{\mathbf{y = 3}}

Solve for variable "x":

\mathbf{10x + 10y - 20z = 80}

\mathbf{Since, \: z = - 2; \quad y = 3}

\mathbf{10x + 10 \times 3 - 20 \times (- 2) = 80}

\mathbf{10x + 10 \times 3 + 20 \times 2 = 80}

\mathbf{10x + 30 + 20 \times 2 = 80}

\mathbf{10x + 30 + 40 = 80}

\mathbf{10x + 70 = 80}

\mathbf{10x + 70 - 70 = 80 - 70}

\mathbf{10x = 10}

Divide by this numbered value \mathbf{10} to get the final value for the variable "x".

\mathbf{\dfrac{10x}{10} = \dfrac{10}{10}}

The numbered values in the numerator and the denominator are the same, on both the sides. This will mean the "x" variable will be left on the left hand side and numbered values "10" will give a product of "1" after the division is done. On the right hand side the numbered values get divided to obtain the final solution for final system of equation for variable "x" as "1".

\boxed{\mathbf{x = 1}}

Final solutions for the respective variables in the form of " (x, y, z) " is:

\boxed{\mathbf{\underline{\Bigg(1, \: \: 3, \: \: - 2 \Bigg)}}}

Hope it helps.
8 0
3 years ago
Read 2 more answers
Order from least to greatest. 10/8, 1.2, 0.556, 0.8%
Vsevolod [243]

The order from least to greatest is 0<u>.8%, 0.556, 1.2 and 10/8</u>

<h3>Ordering of numbers</h3>

In order to order the given numbers, we will first have to write them as a percentage as shown.

Given the number below

10/8, 1.2, 0.556, 0.8%

Convert to percentage

10/8 = 125%

1.2 = 120%

0.556 = 55.6%

0.8%

Hence the order from least to greatest is 0<u>.8%, 0.556, 1.2 and 10/8</u>

Learn more on ordering here; brainly.com/question/12399107

#SPJ1

8 0
2 years ago
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