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djyliett [7]
3 years ago
8

30 points if you answer this question and please show work !

Mathematics
1 answer:
ASHA 777 [7]3 years ago
8 0
h(x)=\dfrac{f(x)}{g(x)}=\dfrac{x^2+x-20}{x+5}=\dfrac{x^2+x+4x-4x-20}{x+5}=\\\\\\=
\dfrac{x^2+5x-4x-20}{x+5}=\dfrac{x(x+5)-4(x+5)}{x+5}=\dfrac{(x+5)(x-4)}{x+5}=\\\\\\=\boxed{x-4}

We see, that g(x) is in denominator, so:

g(x)\neq0\\\\x+5\neq0\\\\\boxed{x\neq-5}

and the domain of h(x) i<span>s the set of all real numbers without x=-5.
</span>
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What is the percent of 840 is 546
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when u do cross multiplication it will be 840x=546 * 100
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4 0
3 years ago
The coordinates of the three vertices of the triangle are A (x1, y1), B (x2, y2), C (x3, y3).
kaheart [24]

Answer:

Step-by-step explanation:

Using the section formula, if a point (x,y) divides the line joining the points (x  

1

​

,y  

1

​

) and (x  

2

​

,y  

2

​

) in the ratio m:n, then  

(x,y)=(  

m+n

mx  

2

​

+nx  

1

​

 

​

,  

m+n

my  

2

​

+ny  

1

​

 

​

)

The vertices of the triangle are given to be (x  

1

​

,y  

1

​

),(x  

2

​

,y  

2

​

) and (x  

3

​

,y  

3

​

). Let these vertices be A,B and C respectively.  

Then the coordinates of the point P that divides AB in l:k will be

(  

l+k

lx  

2

​

+kx  

1

​

 

​

,  

l+k

ly  

2

​

+ky  

1

​

 

​

)

The coordinates of point which divides PC in m:k+l will be  

⎩

⎪

⎪

⎪

⎨

⎪

⎪

⎪

⎧

​

 

m+k+l

mx  

3

​

+(k+l)  

(l+k)

lx  

2

​

+kx  

1

​

 

​

 

​

,  

m+k+l

my  

3

​

+(k+l)  

(l+k)

ly  

2

​

+ky  

1

​

 

​

 

​

 

⎭

⎪

⎪

⎪

⎬

⎪

⎪

⎪

⎫

​

 

⇒(  

m+k+l

kx  

1

​

+lx  

2

​

+mx  

3

​

 

​

,  

m+k+l

ky  

1

​

+ly  

2

​

+my  

3

​

 

​

)

6 0
3 years ago
HELP!!!!! PLEASE!!!!!
emmainna [20.7K]

Answer:

4

Step-by-step explanation:

It's a pythagorean triple

8 0
3 years ago
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Pleas help me find the answer and show the work to this question
lions [1.4K]

Answer:

Leg\ 1 = 8

Leg\ 2 = 15

Step-by-step explanation:

Given: See Attachment

Required

Determine the length of the legs

To do this, we apply Pythagoras theorem.

Hyp^2 = Adj^2 + Opp^2

In this case:

17^2 = x^2 + (2x- 1)^2

Open Bracket

17^2 = x^2 + 4x^2- 2x-2x + 1

17^2 = 5x^2 - 4x + 1

289= 5x^2 - 4x + 1

Collect Like Terms

5x^2 - 4x + 1 - 289 = 0

5x^2 - 4x - 288 = 0

Solving using quadratic formula:

x = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}

So:

x = 8 or x = -7.2

Since, x can't be negative, then:

x = 8

One of the leg is:

Leg\ 1 = x

Leg\ 1 = 8

Leg\ 2 = 2x - 1

Leg\ 2 = 2*8 - 1

Leg\ 2 = 16 - 1

Leg\ 2 = 15

6 0
3 years ago
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