What are these in slope-intercept form? 2y+2x=−8 y+x=−4

Ede4ka [16]

Answer: Use 22/7 for π. Solution: Use the formula. C = 2πr. Substitute 14 for r. C = 2π(14) Substitute 22/7 for π. C ≈ 2 x (22/7) x 14. Simplify C ≈ 2 x (22/1) x 2. C ≈ 88. So, the circumference of the region watered by the sprinkler is about 88 feet.

Step-by-step explanation: Hope this helps

8 0

2 years ago

A line that includes the points (7,u) and (6,6) has a slope of -8. What is the value of u?

Zielflug [23.3K]

Answer:

(6-u)/(6-7)= (6-u)/-1= 8

6 - u = -8

-u = -14

u = 14

8 0

3 years ago

Read 2 more answers

¿Cuál es la ecuación de la recta que pasa por el punto? (-1,-5) y tiene una pendiente de - 1?

Zielflug [23.3K]

Answer:

y=-1x-6

Step-by-step explanation:

y-y1=m(x-x1)

y-(-5)=-1(x-(-1)

y+5=-1(x+1)

y+5=-1x-1

y=-1x-5-1

y=-1x-6

6 0

3 years ago

Any one Know the Answer To This Algebra 1

alexdok [17]

Answer:

The correct answer is B. -3.

Step-by-step explanation:

To solve this problem, we need to plug in -3 for all of the values of x in the equation. If we do this, we get:

f(x) = 2x + 3

f(-3) = 2(-3) + 3

Now, we can just simplify the expression found on the right side of the equation using PEMDAS. First, we should perform the multiplication.

f(-3) = -6 + 3

Next, we should add our final two terms together.

f(-3) = -3

Therefore, the correct answer is -3.

Hope this helps!

3 0

3 years ago

The probability that a student has a Visa card (event V) is .73. The probability that a student has a MasterCard (event M) is .1

snow_lady [41]

We assumed in this answer that the question b is, Are the events V and M independent?

Answer:

(a). The probability that a student has either a Visa card or a MasterCard is $\\ P(V \cup M) = 0.88$ . (b). The events V and M are not independent.

Step-by-step explanation:

The key factor to solve these questions is to know that:

$\\ P(V \cup M) = P(V) + P(M) - P(V \cap M)$

We already know from the question the following probabilities:

$\\ P(V) = 0.73$

$\\ P(M) = 0.18$

The probability that a student has both cards is 0.03. It means that the events V AND M occur at the same time. So

$\\ P(V \cap M) = 0.03$

The probability that a student has either a Visa card or a MasterCard

We can interpret this probability as $\\ P(V \cup M)$ or the sum of both events; that is, the probability that one event occurs OR the other.

Thus, having all this information, we can conclude that

$\\ P(V \cup M) = P(V) + P(M) - P(V \cap M)$

$\\ P(V \cup M) = 0.73 + 0.18 - 0.03$

$\\ P(V \cup M) = 0.88$

Then, the probability that a student has either a Visa card or a MasterCard is $\\ P(V \cup M) = 0.88$ .

Are the events V and M independent?

A way to solve this question is by using the concept of conditional probabilities.

In Probability, two events are independent when we conclude that

$\\ P(A|B) = P(A)$ [1]

The general formula for a conditional probability or the probability that event A given (or assuming) the event B is as follows:

$\\ P(A|B) = \frac{P(A \cap B)}{P(B)}$

If we use the previous formula to find conditional probabilities of event M given event V or vice-versa, we can conclude that

$\\ P(M|V) = \frac{P(M \cap V)}{P(V)}$

$\\ P(M|V) = \frac{0.03}{0.73}$

$\\ P(M|V) \approx 0.041$

If M were independent from V (according to [1]), we have

$\\ P(M|V) = P(M) = 0.18$

Which is different from we obtained previously;

That is,

$\\ P(M|V) \approx 0.041$

So, the events V and M are not independent.

We can conclude the same if we calculate the probability

$\\ P(V|M)$ , as follows:

$\\ P(V|M) = \frac{P(V \cap M)}{P(M)}$

$\\ P(V|M) = \frac{0.03}{0.18}$

$\\ P(V|M) = 0.1666.....\approx 0.17$

Which is different from

$\\ P(V|M) = P(V) = 0.73$

In the case that both events were independent.

Notice that

$\\ P(V|M)*P(M) = P(M|V)*P(V) = P(V \cap M) = P(M \cap V)$

$\\ \frac{0.03}{0.18}*0.18 = \frac{0.03}{0.73}*0.73 = 0.03 = 0.03$

$\\ 0.03 = 0.03 = 0.03 = 0.03$

3 0

3 years ago