well, Diego is 4 now, so by his 18th birthday that'll be 14 years later.
![~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$1600\\ r=rate\to 8.25\%\to \frac{8.25}{100}\dotfill &0.0825\\ t=years\dotfill &14 \end{cases} \\\\\\ A=1600[1+(0.0825)(14)]\implies A=1600(2.155)\implies A=3448](https://tex.z-dn.net/?f=~~~~~~%20%5Ctextit%7BSimple%20Interest%20Earned%20Amount%7D%20%5C%5C%5C%5C%20A%3DP%281%2Brt%29%5Cqquad%20%5Cbegin%7Bcases%7D%20A%3D%5Ctextit%7Baccumulated%20amount%7D%5C%5C%20P%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cdotfill%20%26%20%5C%241600%5C%5C%20r%3Drate%5Cto%208.25%5C%25%5Cto%20%5Cfrac%7B8.25%7D%7B100%7D%5Cdotfill%20%260.0825%5C%5C%20t%3Dyears%5Cdotfill%20%2614%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20A%3D1600%5B1%2B%280.0825%29%2814%29%5D%5Cimplies%20A%3D1600%282.155%29%5Cimplies%20A%3D3448)
60+60×0+1= 61
So your answer is 61.
Hope I Helped!!!
Answer: Perimeter 210
Exclamation: I’m pretty sure you just have to multiply all the sides together
Hope this helps :3
(B)
if <em>f</em>(a) = K, then that means <em>f </em>sends (a) to (K).
the inverse function, <em>f</em>-1, goes back where you started, so <em>f</em>-1 <em />sends (K) to (a).
<em>f</em>-1(K) = a.
75x+2=
75x-2=-2. move the 2 to the other side
75x=-2 now divide 75 both sides
75/75x=-2/75
x=-2/75
