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3 years ago

Plsss hellpppp 14 and 15 plsssssss

Mathematics

1 answer:

Lesechka [4]3 years ago

7 0

Answer:

14). 2nd quadrant

15). 1st quadrant

Step-by-step explanation:

14).Coordinates of a point → J(-8, -12)

Coordinates of the new point J' after reflection of x-axis will follow the rule,

(x, y) → (x, -y)

Coordinates of J' → (-8, 12)

Therefore, point J' will lie in 2nd quadrant.

15). Coordinates of a point → W(-6, 7)

Rule for the rotation by 90°clockwise about the origin,

(x, y) → (y, -x)

Coordinates of point W → (-6, 7)

Following this rule,

W(-6, 7) → W'(7, 6)

Therefore, point W' will lie in the first quadrant.

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In the graph, if the number of manufactured units falls below 6.25, then the business will be operating in what state?

AURORKA [14]

It would be in a state of loss because the units manufactured neither reaches nor exceeds the break even point.

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3 years ago

Modeling Radioactive Decay In Exercise, complete the table for each radioactive isotope.

Travka [436]

Answer :

The amount after 1000 years will be, 5.19 grams.

The amount after 10000 years will be, 0.105 grams.

Step-by-step explanation :

Half-life = 1599 years

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{1599\text{ years}}$

$k=4.33\times 10^{-4}\text{ years}^{-1}$

Now we have to calculate the amount after 1000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 1000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$1000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=5.19g$

Thus, the amount after 1000 years will be, 5.19 grams.

Now we have to calculate the amount after 10000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 10000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$10000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=0.105g$

Thus, the amount after 10000 years will be, 0.105 grams.

4 0

3 years ago

F(x)= (x+1)³ find f(x)¹<br><br>answer plz

Basile [38]

Answer:

f(x)^-1= $\sqrt[3]{x}$ -1

f(x)=x^3+1+3x^2+3x

Step-by-step explanation:

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3 years ago

Pls help, I don’t understand how to do this

MAVERICK [17]

Answer:

5 parts are shaded and 4 parts are white so:

There are 9 parts all together.

We can then form ratio's of the white areas and the shaded areas:

White Area Ratio =

$\frac{4}{9}$

Shaded Area Ratio =

$\frac{5}{9}$

Let the area of sqaure be equated to x, which means let the entire area of the square equal to x:

x = Area of whole square

Now we can form an equation :

$\frac{5}{9} x = 165$

So now we just need to solve for x:

$x = \frac{165}{ \frac{5}{9} }$

$x = 297$

The area of the square is:

$297 {cm}^{2}$

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3 years ago

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Convert the following angle to decimal degree. a=137DEGREES 38' 44"

Norma-Jean [14]

137hahahahacan this be a free.

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3 years ago