Answer:
∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and lies between AB and KM and BK is the transversal line)
m∠MBK ≅ m∠BKM (Angles opposite to equal side of ΔBMK are equal)
Step-by-step explanation:
Given: BK is an angle bisector of Δ ABC. and line KM intersect BC such that, BM = MK
TO prove: KM ║AB
Now, As given in figure 1,
In Δ ABC, ∠ABK = ∠KBC (∵ BK is angle bisector)
Now in Δ BMK, ∠MBK = ∠BKM (∵ BM = MK and angles opposite to equal sides of a triangle are equal.)
Now ∵ ∠MBK = ∠BKM
and ∠ABK = ∠KBM
∴ ∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and BK is the transversal line)
Hence proved.
Answer:
i thinks the answer is the fourth, which an= 3-2(n-1)
Hey there!☺


Equation
−(2x+5)+14=22 Simplify both sides
−2x + −5 + 14 = 22 Distribute
(−2x) + (−5+14) = 22 Combine Like Terms
-2x + 9 = 22
-2x + 9 - 9 = 22 - 9 Subtract 9 from both sides
-2x = 13
-2x/-2 = 13/-2
-13/2 Add the negative to 13
x = -13/2
Hope this helps!