Using it's concept, it is found that there is a 0.0366 = 3.66% probability that your coach and your friend get orange and you get a fruit-punch.
<h3>What is a probability?</h3>
A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.
In this problem, there are 15 bottles.
- 5 are orange, hence the is a 5/15 = 1/3 probability that the coach gets orange, hence P(A) = 1/3.
- After the coach, there will be 14 bottles remaining, of which 4 are orange, hence the probability that the friend gets orange is of P(B) = 4/14 = 2/7.
- For you, there will be 13 bottles remaining, of which 5 will be of fruit-punch, hence the probability you get fruit-punch is of P(C) = 5/13.
The probability of the three outcomes occurring is given by:

0.0366 = 3.66% probability that your coach and your friend get orange and you get a fruit-punch.
More can be learned about probabilities at brainly.com/question/14398287
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For the answer to the question above, I've used my calculator to inverse your given equation because my brain can't do that.
The answer to your question is
In radians, arcsin(sin(9π) / 7) = 0.
i hope my answer helped you.
Answer:
C is a letter on the alphabet
Step-by-step explanation:
you havent included any pictures so i dont know what you mean
Answer:
answer = 12.87 km/h
Step-by-step explanation:
Given
Ship A is sailing east at 25 km/h = 
ship B is sailing north at 20 km/h =
here x and y are the sailing at t = 4 : 00 pm for ship A and B respectively
so we get x = 4 ×25 =100 km/h
y = 4× 20 = 80 km/h
let z is the distance between the ships, we need to find
at t = 4 hr
At noon, ship A is 130 km west of ship B (12:00 pm)
so equation will be


derivative first equation w . r. to t we get



![\frac{dz}{dt} =\frac{1}{z}[(x -130)\frac{dx}{dt} +y\frac{dy}{dt}]](https://tex.z-dn.net/?f=%5Cfrac%7Bdz%7D%7Bdt%7D%20%3D%5Cfrac%7B1%7D%7Bz%7D%5B%28x%20-130%29%5Cfrac%7Bdx%7D%7Bdt%7D%20%2By%5Cfrac%7Bdy%7D%7Bdt%7D%5D)

