Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.
So there are 3 clubs:
- Club A, with 10 students.
- Club B, with 4 students.
- Club C, with 5 students.
The possible combinations of 2 students from different clubs are
- Club A with club B
- Club A with club C
- Club B with club C.
The number of combinations for each of these is given by the product between the number of students in the club, so we get:
- Club A with club B: 10*4 = 40
- Club A with club C: 10*5 = 50
- Club B with club C. 4*5 = 20
For a total of 40 + 50 + 20 = 110 different combinations.
This means that there are 110 different ways in which 2 students from different clubs can be selected.
If you want to learn more about combination and selections, you can read:
brainly.com/question/251701
Answer:
It is 80
Step-by-step explanation:
Percentage Calculator: 240 is what percent of 300? = 80.
Which of the following equations is written in standard form?
C. 20y=20
9514 1404 393
Answer:
- 2 complex roots
- 2 positive real roots
- 0 negative real roots
Step-by-step explanation:
The signs of the terms are + - - +. There are two sign changes, so 0 or 2 positive real roots.
Negating the signs of the odd-degree terms, the signs are + + + +. There are no sign changes, so 0 negative real roots.
For x=0, the value of the quartic is +3. For x=1, the value is -3, so we know there are 2 positive real roots, one of which lies in the interval (0, 1).
The 4th-degree polynomial equation must have 4 roots, so the other two must be complex.
- 2 complex roots
- 2 positive real roots
- 0 negative real roots
_____
The roots are approximately 0.489999841592, 2.06573034434, −0.777865092969 ± 1.53582061225i
