23=x-9;x+14 I need help with this problem.
1 answer:
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To take out terms outside the radical we need to divide the power of the term by the index of the radical; the quotient will be the power of the term outside the radical, and the remainder will be the power of the term inside the radical.
First, lets factor 8:
Now we can divide the power of the term, 3, by the index of the radical 2:
= 1 with a remainder of 1
Next, lets do the same for our second term
:
= 3 with a remainder of 1
Again, lets do the same for our third term
:
with no remainder, so this term will come out completely.
Finally, lets take our terms out of the radical:
We can conclude that the correct answer is the third one.
First, lets factor 8:
Now we can divide the power of the term, 3, by the index of the radical 2:
Next, lets do the same for our second term
Again, lets do the same for our third term
Finally, lets take our terms out of the radical:
We can conclude that the correct answer is the third one.