We compute for the side lengths using the distance formula √[(x₂-x₁)²+(y₂-y₁)²].
AB = √[(-7--5)²+(4-7)²] = √13
A'B' = √[(-9--7)²+(0-3)²] = √13
BC = √[(-5--3)²+(7-4)²] = √13
B'C' = √[(-7--5)²+(3-0)²] =√13
CD = √[(-3--5)²+(4-1)²] = √13
C'D' = √[(-5--7)²+(0--3)²] = √13
DA = √[(-5--7)²+(1-4)²] = √13
D'A' = √[(-7--9)²+(-3-0)²] = √13
The two polygons are squares with the same side lengths.
But this is not enough information to support the argument that the two figures are congruent. In order for the two to be congruent, they must satisfy all conditions:
1. They have the same number of sides.
2. All the corresponding sides have equal length.
3. All the corresponding interior angles have the same measurements.
The third condition was not proven.
Answer:
That sucks.
Step-by-step explanation:
Answer:
11 units
Step-by-step explanation:
simply subtract -3 from 8, which is the same as adding 3 and 8, so the answer is 11 units.
<span>1000 cm^2(1 meter/100 cm)(1 meter/100 cm) = 1000/(100)^2 square meters
= 1000/10000 sq. meters = 1/10 sq. meters</span>
Step-by-step explanation:
Breadth = 8m
Length = 8m + 4m = 12m
Area of the rectangle = length × breadth, 12m × 8m = 96m square.
