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3 years ago

Please help!!! from plato

Mathematics

1 answer:

damaskus [11]3 years ago

7 0

The coordinates of vertex A', vertex B' and vertex C' are (-8, 4) , (-12, 12) and (-4, 12) respectively.

Explanation

According to the given diagram of triangle ABC, the co ordinates of the vertices are: $A=(-2,1), B=(-3,3)$ and $C= (-1,3)$

If triangle ABC is dilated by a scale factor of 4 to form triangle A'B'C' , then we need to multiply each co ordinate by the scale factor of 4.

So, the co ordinate of A' will be: $(-2*4, 1*4)=(-8,4)$

the co ordinate of B' will be: $(-3*4, 3*4)=(-12,12)$ and

the co ordinate of C' will be: $(-1*4, 3*4)=(-4,12)$

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Given that 3x+2y=5a+b and 4x-3y=a+7b, solve for y-x in terms of a and b.

Eduardwww [97]

Answer:

y - x = - 2 b

Step-by-step explanation:

Given-

3 x + 2 y = 5 a + b...................(i)

4 x - 3 y = a + 7 b.....................(ii)

Multiply by 3 and 2 in equation (i) & (ii) respectively-

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2 years ago

Simplified form of 12x-1 = 2(6+5x) +7

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X=10

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3 years ago

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Solve -5 + w divided by 3 = -1. 12 -12 2 -2

son4ous [18]

Hello!

Answer:

w=12

*The answer must have a positive sign.*

Step-by-step explanation:

First, you add by 5 from both sides of an equation.

$-5+\frac{w}{3}+5=-1+5$

Then, you simplify.

$\frac{w}{3}=4$

Next, you multiply by 3 from both sides of an equation.

$\frac{3w}{3}=4*3$

And finally, simplify and solve. You can also multiply by the numbers from left too right.

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Final answer: → $w=12$

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2 years ago

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FrozenT [24]

Answer:

A. 5

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Step-by-step explanation:

What you do is you substitute -2 into the a and the 3 into the b.

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3 years ago

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