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Marysya12 [62]
3 years ago
9

Determine the equivalent system for the given system of equations:

Mathematics
1 answer:
Alenkinab [10]3 years ago
7 0

Answer:

They are an equivalent system and the values are x=17/37 and y=-16/37

Step-by-step explanation:

Systems of equations that have the same solution are called equivalent systems.

Given a system of two equations, we can produce an equivalent system by replacing one equation by the sum of the two equations, or by replacing an equation by a multiple of itself.

(-4)*(5x + 3y = 1) → -20x - 12y = -4

(5)*(4x − 5y = 4) → 20x - 25y =20

Add the last 2 eq →  -37y= 16 →  y= - 16/37

replace this value in any equation of the system.

5x + 3(-16/37) = 1 →  x= (1 +48/37)/ 5 =(37/37 + 48/37)/5=(85/37)/5 = 17/37

We have x and y values. Replace this values in both equation and verify the result

5x + 3y = 1  → 85/37 -48/37 =37/37=1

4x − 5y = 4 → 68/37 + 80/37= 148/37= 4

So, in fact, they are a equivalent system

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Answer:

49°

Step-by-step explanation:

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Find the measure of angle X in the triangle below.
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Answer:

  X = 89.92° or 90.08°

Step-by-step explanation:

The law of sines can be used to find the value of angle X:

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<em>Comment on the problem</em>

We suspect that the angle is supposed to be considered to be 90°. However, the given angle is reported to 2 decimal places, so we figure the requested angle should also be reported to 2 decimal places.

The lengths of the short side that correspond to the above angles are 10.03 and 9.97 units. If the short side were considered to be 10 units, the triangle would be a right triangle, and the larger acute angle would be ...

  arcsin(24/26) ≈ 67.38014° . . . . rounds to 67.38°

This points up the difficulty of trying to use the Law of Sines on a triangle that is actually a right triangle.

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