<span>1. (f+g)(x) = f(x) +g(x)
.. = (</span>x^2-36) +(<span>x^3+2x^2-10)
.. = x^3 +3x^2 -46
2. </span>(f•g)(x) = f(x)•g(x)
.. = (x^4-9)•(x^3+9)
.. = x^7 +9x^4 -9x^3 -81
<span>3. (f-g)(x) = f(x) -g(x)
.. = (x^3-2x^2+12x-6) -(4x^2-6x+4)
.. = x^3 -6x^2 +18x -10</span>
Answer:
Yes the ladder is safe because 59.25 degrees < 75 degrees
Step-by-step explanation:
In the below photos I have included a screenshot of the equation I used, which I got from another user, and my work with an unfinished diagram and completed equations to the side
Answer:
Both functions have one x-intercept each.
Step-by-step explanation:
The first function is

This is a parabola with vertices at the origin and has one x-intercept at t=0.
The transformed function is

The function g(t) is obtained by shifting the graph of f(t) to the left by 3 units.
This graph also has one x-intercept at x=-3.
Therefore both functions has the same number of x-intercepts
20% is equal to 0.2
0.2 times 26.40 is equal to 5.28
26.40 minus 5.28 is equal to 21.12
Don't touch the center. It is already even.
Start anywhere by connecting a dotted line from one vertex to the next. To keep things so we know what we are talking about, go clockwise. Now you have 2 points that are Eulerized that were not before.
Skip and edge and do the same thing to the next two vertices. Those two become eulerized. Skip an edge and do the last 2.
Let's try to describe this better. Start at any vertex and number them 1 to 6 clockwise.
Join 1 to 2
Join 3 to 4
Join 5 to 6
I think 3 is the minimum.
3 <<<< answer