Answer:
the numerical value of the correlation between percent of classes attended and grade index is r = 0.4
Step-by-step explanation:
Given the data in the question;
we know that;
the coefficient of determination is r²
while the correlation coefficient is defined as r = √(r²)
The coefficient of determination tells us the percentage of the variation in y by the corresponding variation in x.
Now, given that class attendance explained 16% of the variation in grade index among the students.
so
coefficient of determination is r² = 16%
The correlation coefficient between percent of classes attended and grade index will be;
r = √(r²)
r = √( 16% )
r = √( 0.16 )
r = 0.4
Therefore, the numerical value of the correlation between percent of classes attended and grade index is r = 0.4
Answer:
5.95
Step-by-step explanation:
3.25 + 2 7/10 = 3.25 + 2.70 = 5.95
Answer:
C is the answer
Step-by-step explanation:
The domain can't be minus. That's the only stipulation. It can be equal to 0 or anything larger than 0. It just can't go into the minus numbers.
0≤x<infinity.
C
154/10=15.4. Then apply greatest integer function (smallest integer larger than that number) to get 16.
Answer:
3.5 pounds for 14 people
Step-by-step explanation:
Given
1 pound = 4 people
Required
Determine the pounds for 14 people
Represent this with x; so, we have:
Cross Multiply
Solve for x
<em>Hence, 3.5 pounds for 14 people</em>
