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mario62 [17]
3 years ago
15

Compare. Write <, >, or =1.538 and 1.54​

Mathematics
1 answer:
Elena L [17]3 years ago
3 0

Answer:

1.54 > 1.538

Step-by-step explanation:

The 1.54 is a higher number because the 4 in its place value will be automatically higher than 1.538 because in its place value it's a 3. If you need anymore help just contact me with my account.

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The 2008 Workplace Productivity Survey, commissioned by LexisNexis and prepared by WorldOne Research, included the question, "Ho
vitfil [10]

Answer:

Therefore, the sampling distribution of \bar{x} is normal with a mean equal to 9 hours and a standard deviation of 0.7969 hours.

The 95% interval estimate of the population mean \mu is

LCL = 7.431 hours to UCL = 10.569 hours

Step-by-step explanation:

Let X be the number of hours a legal professional works on a typical workday. Imagine that X is normally distributed with a known standard deviation of 12.6.

The population standard deviation is  

\sigma = 12.6 \: hours

A sample of 250 legal professionals was surveyed, and the sample's mean response was 9 hours.

The sample size is

n = 250

The sample mean is  

\bar{x} = 9 \: hours  

Since the sample size is quite large then according to the central limit theorem, the sample mean is approximately normally distributed.

The population mean would be the same as the sample mean that is

 \mu = \bar{x} = 9 \: hours

The sample standard deviation would be  

$ s = {\frac{\sigma}{\sqrt{n} }  $

Where   is the population standard deviation and n is the sample size.

$ s = {\frac{12.6}{\sqrt{250} }  $

s = 0.7969 \: hours

Therefore, the sampling distribution of \bar{x} is normal with a mean equal to 9 hours and a standard deviation of 0.7969 hours.

The population mean confidence interval is given by

\text {confidence interval} = \mu \pm MoE\\\\

Where the margin of error is given by

$ MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $ \\\\

Where n is the sampling size, s is the sample standard deviation and  is the t-score corresponding to a 95% confidence level.

The t-score corresponding to a 95% confidence level is

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025

Degree of freedom = n - 1 = 250 - 1 = 249

From the t-table at α = 0.025 and DoF = 249

t-score = 1.9695

MoE = t_{\alpha/2}(\frac{\sigma}{\sqrt{n} } ) \\\\MoE = 1.9695\cdot \frac{12.6}{\sqrt{250} } \\\\MoE = 1.9695\cdot 0.7969\\\\MoE = 1.569\\\\

So the required 95% confidence interval is

\text {confidence interval} = \mu \pm MoE\\\\\text {confidence interval} = 9 \pm 1.569\\\\\text {LCI } = 9 - 1.569 = 7.431\\\\\text {UCI } = 9 + 1.569 = 10.569

The 95% interval estimate of the population mean \mu is

LCL = 7.431 hours to UCL = 10.569 hours

8 0
3 years ago
Mary took out a student loan for $15,000 at 4% simple interest. how much interest will she pay after 10 years
hammer [34]

Answer:

18,274

Step-by-step explanation:

7 0
3 years ago
24 lb turkey for 15 people​
lord [1]

Answer:

Each person gets 1.6 of the turkey

Step-by-step explanation:

24/15 = 1.6

8 0
3 years ago
Simplify 4^7/5^2 all raised to the 3rd power<br><br> 4^10/5^5<br> 4^4/5<br> 4^21/5^6<br> 12^7/15^2
zepelin [54]
[4^7/5^2]³ = 4^21/5^6

When a power is raised to an other power, you multiply these 2 powers

Answer: 4^21/5^6
5 0
3 years ago
A right triangle has a hypotenuse of 15 cm. What are possible lengths for the two legs of the triangle. Explain your answer.
Ostrovityanka [42]

Answer: 15, 3 and 6

Step-by-step explanation: The other leg is 2 × 3 = 6

5 0
3 years ago
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