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4 years ago

Compare. Write <, >, or =1.538 and 1.54

Mathematics

1 answer:

Elena L [17]4 years ago

3 0

Answer:

1.54 > 1.538

Step-by-step explanation:

The 1.54 is a higher number because the 4 in its place value will be automatically higher than 1.538 because in its place value it's a 3. If you need anymore help just contact me with my account.

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Last June only 0.17 inches of rain fell all month. What is the difference between the average rainfall and the actual rainfall f

spin [16.1K]

Answer:

Part 1) 0.50 inches

Part 2) 1.14 inches

Part 3)

a) 1.25 inches

b) -0.32 inches

Step-by-step explanation:

The complete question in the attached figure

Part 1) Last June only 0.17 inches of rain fell all month. What is the difference between the average rainfall and the actual rainfall for the last June

Let

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

The difference between the average rainfall and the actual rainfall for the last June is given by the expression

$(x-y)$

we have

$x=0.67\ in\\y=0.17\ in$

substitute

$0.67-0.17=0.50\ in$

Part 2) The departure from the average rainfall last July was -0.36 inches. How much rain fell last July?

we know that

The departure from the average is the difference between the actual amount of rain and the average amount of rain for a given month

Let

D -----> the departure from the average

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

$D=y-x$

we have

$D=-0.36\ in\\x=1.5\ in$

substitute the given values

$-0.36=y-1.5$

solve for y

$y=1.5-0.36\\y=1.14\ in$

Part 3)

<u>Part a)</u> How much rain would have to fall in August so that the total amount of rain equals the average rainfall for these three months?

<u>Part b</u>) What would the departure from the average be in August in that

situation?

Part a) How much rain would have to fall in August so that the total amount of rain equals the average rainfall for these three months?

Find the average rainfall for these three months

Adds the average rainfall and divide by 3

$(0.67+1.5+1.57)/3=1.25\ in$

Part b) What would the departure from the average be in August in that

situation?

we know that

The departure from the average is the difference between the actual amount of rain and the average amount of rain for a given month

Let

D -----> the departure from the average

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

$D=y-x$

we have

$x=1.57\ in\\y=1.25\ in$

substitute the given values

$D=1.25-1.57=-0.32\ in$

7 0

4 years ago

A man who moves to a new city sees that there are two routes he could take to work. A neighbor who has lived there a long time t

Mandarinka [93]

Answer:

(a) Confidence Interval for Route A is (38.61, 41.39)min

Confidence Interval for Route B is (42.07, 43.93)min

(b) No

Step-by-step explanation:

(a) Route A

Mean=40min, sd=3min, df=33.1, t=2.0675, n=20

CI = (mean + or - t×sd/√n)

CI = (40 + 2.0675×3/√20) = 40+1.39 = 41.39min

CI = (40 - 2.0675×3/√20) = 40 - 1.39 = 38.61min

CI for Route A is (38.61,41.39)min

Route B

Mean=43min, sd=2min, t=2.0675, n=20

CI = (43 + 2.0675×2/√20) = 43+ 0.93 = 43.93min

CI = (43 - 2.0675×2/√20) = 43 - 0.93 = 42.07min

CI for Route B is (42.07,43.93)min

(b) He should not believe the old timer's claim. The man saves an average of 3 minutes a day by driving Route A

3 0

3 years ago

Read 2 more answers

Explain how you know whether to add or subtract when you use the Distributive property to multiply

nirvana33 [79]

The distributive property of multiplication over addition can be used when you multiply a number by a sum. The distributive property lets you multiply a sum by multiplying each addend separately and then add the products:

$a\cdot (b+c)=a\cdot b+a\cdot c.$

The distributive property of multiplication over subtraction can be used when you multiply a number by a difference. The property states that the product of a number and the difference of two other numbers is equal to the difference of the products:

$a\cdot (b-c)=a\cdot b-a\cdot c.$