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Vinil7 [7]
3 years ago
10

PLEASE HELP PLEASE HELP PLEASE HELP

Mathematics
2 answers:
natta225 [31]3 years ago
7 0
Did the guy already help
blagie [28]3 years ago
4 0
0.048 x 10000 = 480 one year is $480 so double that it’s 960 so $960 interest for two years - also for question one i believe the answer is just $10000 not “b”
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117 is 0.9% of what number. Would you expect the answer to be a lot less than 117, slightly less than 117, slightly greater than
kondor19780726 [428]

Answer:

13,000. A lot greater as its 99.1% more.

Step-by-step explanation:

calculator shall guide you.

6 0
3 years ago
Write the equation of the line that passes through (-4, 3) and is perpendicular to the line y = 7/5x -3/5
tensa zangetsu [6.8K]

Answer:

y = -\frac{5}{7}x + \frac{1}{7}

Step-by-step explanation:

3 = −5⁄7[−4] + b

2 6⁄7

\frac{1}{7} = b \\ \\ y = -\frac{5}{7}x + \frac{1}{7}

Perpendicular Lines have OPPOSITE MULTIPLICATIVE INVERSE <em>RATE</em><em> </em><em>OF</em><em> </em><em>CHANGES</em><em> </em>[<em>SLOPES</em>], so 1 2⁄5 [or 7⁄5] becomes −5⁄7.

I am joyous to assist you anytime.

8 0
3 years ago
Write 5 5/32 as a decimal.​
kati45 [8]

5 5/32 as a decimal is 0.15265

6 0
3 years ago
Can someone please help me on this I beg you please
ANEK [815]

Answer:

b

Step-by-step explanation:

b

6 0
3 years ago
Lieutenant Commander Data is planning to make his monthly (every 30 days) trek to Gamma Hydra City to pick up a supply of isolin
Nookie1986 [14]

Answer:

a

 N  =  209 \ unites

b

 N_{max}  =  249  

Step-by-step explanation:

From the question we are told that

   The daily demand is  d =  7/day

   The  standard deviation is  \sigma  =  3 /day

   The  service probability is  s =  95\%  =  0.95

    The number of chips  in the inventory is k  =  40

   The number of days in his monthly is  T =  30 \  days

    The lead time is  L  =  4

 

Generally the number he should order (optimal order ) is mathematically represented as

      N  =  d(L  +  T)+(\sigma_{T + L}  * z)  -k

Here \sigma__{T+L }} is the monthly standard deviation which is mathematically evaluated as

            \sigma__{T  + L}} =  \sqrt{(T + L) * 1^2}

=>         \sigma__{T  + L}}  =  \sqrt{34}

=>          \sigma__{T+L}} =  5.83

Also  z-value  for the  95% service probability  from the z-table  is  1.96

So

      N  =  7 *  (30 +4 ) + (1.96 *  5.83) - 40

=>     N  =  209 \ unites

For the maximum order quantity  k =  0

So

    N_{max} = d(L  +  T)+(\sigma_{T + L}  * z)  -0

=> N_{max}  =  7 *  (30 +4 ) + (1.96 *  5.83) - 0

=>  N_{max}  =  249  

7 0
3 years ago
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