Ask question

Ask question

All categories

Irina-Kira [14]

3 years ago

9

Jonathan runs 4 days a week. Each day, he runs 4 laps that are each 2 miles long. He spends 208 minutes running each week. He ru

ns each mile in the same amount of time.

1 answer:

fredd [130]3 years ago

4 0

4 laps x 2 miles = 8 miles total

8 miles x 4 days = 32 total miles per week

208 / 32 = 6.5 minutes per mile

You might be interested in

11 minus the product of 5 and a number k

Alex787 [66]

This would be displayed as 11 - 5k

This cannot be solved, however, without knowing the value of k, or at least what the expression is equal to.

7 0

3 years ago

Stuart paid $ 48.00 for a New tennis racket ,which was 64% of the original price what was the original price of the racket.

Trava [24]

Seventy five dollars hope this could help[

5 0

3 years ago

Consider an espresso stand with a single barista. Customers arrive at the stand at the rate of 28 per hour according to a Poisso

Snowcat [4.5K]

Answer:

The average number of customers in the system is 3.2

Step-by-step explanation:

The average number of customes in the system is given by:

$L = \frac{\lambda^{2}}{\mu(\mu - \lambda)}$

In which

$\lambda$ is the number of arirvals per time period

$\mu$ is the average number of people being served per period.

The number of arrivals is modeled by the Poisson distribution, while the service time is modeled by the exponential distribution.

Customers arrive at the stand at the rate of 28 per hour

This means that $\lambda = 28$

Service times are exponentially distributed with a service rate of 35 customers per hour.

This means that $\mu = 35$ . So

The average number of customers in the system (i.e., waiting and being served) is

$L = \frac{\lambda^{2}}{\mu(\mu - \lambda)}$

$L = \frac{28^{2}}{35(35 - 28)} = 3.2$

The average number of customers in the system is 3.2

4 0

3 years ago

The higher interest rate of a cash advance on a credit card with an existing balance can be eliminated by paying the cash advanc

finlep [7]

The answer is False.

8 0

2 years ago

Read 2 more answers

Two experiments are defined below. An event is defined for each of the experiments. Experiment I: Corrine rolls a standard six-s

-BARSIC- [3]

Answer: The correct answer is option C: Both events are equally likely to occur

Step-by-step explanation: For the first experiment, Corrine has a six-sided die, which means there is a total of six possible outcomes altogether. In her experiment, Corrine rolls a number greater than three. The number of events that satisfies this condition in her experiment are the numbers four, five and six (that is, 3 events). Hence the probability can be calculated as follows;

P(>3) = Number of required outcomes/Number of possible outcomes

P(>3) = 3/6

P(>3) = 1/2 or 0.5

Therefore the probability of rolling a number greater than three is 0.5 or 50%.

For the second experiment, Pablo notes heads on the first flip of a coin and then tails on the second flip. for a coin there are two outcomes in total, so the probability of the coin landing on a head is equal to the probability of the coin landing on a tail. Hence the probability can be calculated as follows;

P(Head) = Number of required outcomes/Number of all possible outcomes

P(Head) = 1/2

P(Head) = 0.5

Therefore the probability of landing on a head is 0.5 or 50%. (Note that the probability of landing on a tail is equally 0.5 or 50%)

From these results we can conclude that in both experiments , both events are equally likely to occur.

3 0

3 years ago