There is no solution ,<span>a+c=-10;b-c=15;a-2b+c=-5 </span>No solution System of Linear Equations entered : [1] 2a+c=-10
[2] b-c=15
[3] a-2b+c=-5
Equations Simplified or Rearranged :<span><span> [1] 2a + c = -10
</span><span> [2] - c + b = 15
</span><span> [3] a + c - 2b = -5
</span></span>Solve by Substitution :
// Solve equation [3] for the variable c
<span> [3] c = -a + 2b - 5
</span>
// Plug this in for variable c in equation [1]
<span><span> [1] 2a + (-a +2?-5) = -10
</span><span> [1] a = -5
</span></span>
// Plug this in for variable c in equation [2]
<span><span> [2] - (-? +2b-5) + b = 15
</span><span> [2] - b = 10
</span></span>
// Solve equation [2] for the variable ?
<span> [2] ? = b + 10
</span>
// Plug this in for variable ? in equation [1]
<span><span> [1] (? +10) = -5
</span><span> [1] 0 = -15 => NO solution
</span></span><span>No solution</span>
Answer:
The correct option is A) 3 square inches; 
.
Step-by-step explanation:
It is given that the length of the frame is (2x-3) and the width is (x-2)
The area of the rectangle is: 
Where, A is the area l is the length and w is the width of the rectangle.
Put 
and 
in the area of the rectangle.
The area of the frame expressed as a polynomial is .
Now substitute x=3 in 
.
The area of the frame is 3 square inches.
Hence, the correct option is A) 3 square inches; .
Answer:
f(5) = 13
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
<u>Algebra I</u>
- Function notation and substitution
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = x² - 12
x = 5
<u>Step 2: Evaluate</u>
- Substitute: f(5) = 5² - 12
- Exponents: f(5) = 25 - 12
- Subtract: f(5) = 13
Answer:
x = - 3 ± 
Step-by-step explanation:
Given
4x² + 24x = 4 ( divide through by 4 )
x² + 6x = 1
To complete the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(3)x + 9 = 1 + 9
(x + 3)² = 10 ( take the square root of both sides )
x + 3 = ± ( subtract 3 from both sides )
x = - 3 ±
