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Sholpan [36]
3 years ago
8

Help me please or I fail this year

Mathematics
2 answers:
Solnce55 [7]3 years ago
5 0
A is the correct answer.
Cerrena [4.2K]3 years ago
4 0
I can’t see the picture properly so I can’t assist you furthermore try to get the picture more clear
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Suppose we have four integers, no two of which are congruent $\pmod 6$. Let $N$ be the product of the four integers. If $N$ is n
aalyn [17]

Answer:

4

Step-by-step explanation:

Given:

A, B, C, D have distinct positive values for mod 6

A (mod 6) = 1

B (mod 6) = 2

C (mod 6) = 4

D (mod 6) = 5

Each mod 6 value cannot be a zero since the product ABCD is not a multiple of 6.

Furthermore, in order that ABCD mod 6 > 0, we cannot  have a residue equal to 3, else the product with a residue 2 or 4 will make the product a multiple of 6.

Thus the only positive residues can only be 1,2,4,5

A*B*C*D  (mod 6) > 0  = 1*2*4*5 (mod 6) = 4

4 0
4 years ago
Helppppppppppppppppppppppppppppppppppppppppppppppppppppppp
Fynjy0 [20]
The answer is 4, just plug it in
4 0
3 years ago
Read 2 more answers
A standard deck of cards has 52 cards. The cards have one of two colors: 26 cards in the deck are red and 26 are black. The card
goldfiish [28.3K]

Answer:

Given:

The cards have one of four denominations:

13 cards are hearts (red),

13 cards are diamonds (red),

13 cards are clubs (black), and

13 cards are spades (black).

a) One card is selected at random and the denomination is recorded. What is the sample space S for the set of possible outcomes?

Sample sample S = {heart, diamond, spade, club} as we only have four types of denominations. It means we can get one of the denominations at a a time, that is why the we have the sample space S.

b) Two cards are selected at random and the color is recorded. What is the sample space S for the set of possible outcomes?

Here, we are talking about colors, and we have two types of color black and red, so the sample space will be

As we are selecting two cards at random, so each element in the sample space will be the combination of two colors, and the set of possible outcomes are 4 (2^2 = 4) which is

S = {(black, black), (black, red), (red, black),(red, red)}

c)Two cards are selected at random and the denomination is recorded. The event H is defined as the event that the first card is hearts. What defines event H?

Here, we are talking about denominations, and we have four types of denominations, so the sample space H will be

As given, the first card is heart,

H = {(heart, heart), (heart, diamond), (heart, spade), (heart, club)}

we can get either of the combination from H provided in all combination first card is heart, and other card could be any of the four denomination. .

d)Two cards are selected at random and the denomination is recorded. The event D is defined as the event that the first card is diamonds and the second card is red. What defines event DC?

Here, we are talking about denominations and colors, and we have four types of denominations and two colors,

As given first card is diamond it second card will be of red color and we know that heart and diamond in the deck of cards are of red color, so the sample space D will be

D = {(Diamond, heart), (diamond, diamond)}

It means we have only two options.

e)Two cards are selected at random. Event C is defined as the event that the first card is clubs, event R as the event that the first card is red, and event B as the event that the second card is black. Which events are disjoint?

Disjoint events in probability means that the events have no outcomes in common.

For event C, first card is club, so the outcome is

C = {(club, heart), (club, diamond), (club, spade), (club, club)}

For event R, first card is red, so the outcome is

R = {(red, black),(red, red)}

For event B, second card is black, so the outcome is

B = {(red, black),(black, black)}

Here we can see events R and B have one outcome as common which is {red, black} and C has nothing in common among all.

So the event C is disjoint.  

4 0
3 years ago
1)Which of the ordered pairs is NOT a
Butoxors [25]

Answer:

a) {(3,3),(3,4),(4,5),(4,6)}

Step-by-step explanation:

Given

(a) to (d)

Required

Which is not a function

A relation is represented as:

\{(x_1,y_1),(x_1,y_1),(x_2,y_2),...............(x_0,y_0)\}

For the relation t be a relation, then:

x_i \ne x_jwhere i \ne j

This means that none of the x values must be related.

The first relation has 3 repeated as its value of . Hence, (a) is a relation

8 0
3 years ago
Between which two integers would you plot the square root of 19 on a number line?a.2 and 3 b.3 and 4 c.4 and 5 d.5 and 6
DiKsa [7]
The two integers would probably be b. 4 and 3
8 0
3 years ago
Read 2 more answers
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