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nikklg [1K]
3 years ago
7

A polynomial function upper P left parenthesis x right parenthesis with rational coefficients has the given roots. Find two addi

tional roots of upper P left parenthesis x right parenthesis equals 0. i and 7 + 8i
Mathematics
1 answer:
mylen [45]3 years ago
5 0

Given that a polynomial function P(x) has rational coefficients.

Two roots are already given which are i and 7+8i,

Now we have to find two additional roots of P(x)=0

Given roots i and 7+8i are complex roots and we know that complex roots always occur in conjugate pairs so that means conjugate of given roots will also be the roots.

conjugate of a+bi is given by a-bi

So using that logic, conjugate of i is i

also conjugate of 7+8i is 7-8i

Hence final answer for the remaining roots are (-i) and (7-8i).

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OK.  These problems are easy if you know the quadratic formula,
and they're impossible if you don't.

Here's the quadratic formula:

When the equation is in the form of      Ax² + Bx + C = 0

then                    x =  [ -B plus or minus √(B²-4AC) ] / 2A

I'm sure that formula is in your text or your study notes,
right before these questions.  You should cut it out or
copy it, and tape it inside the cover of your notebook.
Then, you'll always have it when you need it, until
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The first question says        3x²  +  5x  +  2  = 0

Is this in the form of             Ax²  +  Bx  +  C  = 0    ?

             Yes !                    A=3      B=5   C=2

             so you can use the quadratic formula to solve it.

            x =  [ -B plus or minus √(B²-4AC) ] / 2A

               =  [ -5 plus or minus √(5² - 4·3·2) ] / 2·3

               =  [ -5 plus or minus √(25 - 24)  ]  /  6

               =  [  -5 plus or minus  √1          ]  /  6

           x  =        -4 / 6  =  -2/3
and
           x  =        -6 / 6  =  -1 .    
_______________________________________

The second question says

                                         4x²  +  5x  -  1 = 0

Is this in the form of          Ax²  +  Bx + C = 0  ?

           Yes it is !            A=4     B=5   C= -1  

         so you can use the quadratic formula to solve it.

            x =  [ -B plus or minus √(B²-4AC) ] / 2A

Now, you take it from here.

6 0
3 years ago
1/3x+4=x-2<br><br><br> SHOW WORK
Len [333]
X= -3
I hope that helps :)

8 0
3 years ago
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