Answer:
The minimum amount of breaking strain the crane can handle is 6350 kg. (Since it is measured to 2 sig. figs, 6349 kg would round down to 6300 kg, hence the min. is 6350 kg.)
The maximum weight of each crate would be 94 kg. (Since it is measured to the nearest 10 kg, 95 kg would round up to 100 kg, hence the max. is 94 kg.)
Therefore, the greatest number of crates that can be safely lifted would be (6350/94) crates which is 67.5 crates, which rounded down is 67 crates.
All numbers are taken as integers in this answer.
Step-by-step explanation:
Hope this helped!
Yes, very fun, not
ok
one way is table or
solutions amount x and y
x+y=500
x=25%
y=50%
0.25x+0.5y=0.35(500)
we have
x+y=500
0.25x+0.5y=0.35(500)
0.25x+0.5y=175
solve
multiply second equation by 100
25x+50y=17500
divide everybody by 25
x+2y=700
now we have
x+y=500
x+2y=700
multiply first equation by -1 and add to second equaiton
-x-y=-500
<u>x+2y=700 +</u>
0x+1y=200
y=200
sub
x+y=500
x+200=500
x=300
300L of the 25% and 200L of the 50%
I had the same thing what school do you go to i got it wrong
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