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BlackZzzverrR [31]
3 years ago
10

Minhaoh i need help go to my profile the qustion will be there

Mathematics
2 answers:
inessss [21]3 years ago
5 0

Answer:

1/4

Step-by-step explanation:

(-7,2) (1,4)

gtnhenbr [62]3 years ago
3 0

Answer:

What do you need help with

Step-by-step explanation:

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A cliff diver jumps from a cliff that is 96 feet above the water. His jump can be modeled by a quadratic equation, h= -16t(expon
ladessa [460]

Answer:

The diver will take 2.449 seconds to enter the water.

Step-by-step explanation:

We have been given that quadratic equation for the diver jumps is

h=-16t^2+96

We have to find the time taken for the diver to enter the water. When the diver enters the water, the height becomes zero.

0=-16t^2+96\\\\16t^2=96\\\\t^2=6\\\\t=\sqrt6\\\\t=2.449\text{ seconds}

Therefore, the diver will take 2.449 seconds to enter the water.

4 0
3 years ago
Circular garden in the middle of a square yard. The radius of the circle is 4x. The side length of the yard is 20x. What is the
dusya [7]
-- The area of the entire yard, before the garden was planted, was

             (side)²  =  (20x)²  =  400 x² .

-- The area of the circle where garden was put in is

             pi R²  =  (pi) · (4x)²  =  16 pi x² .

--  The remaining area of the yard ... the part not covered by
the circular garden ... is

           (400x²) - (16pi x²)  =  x² (400 - 16pi)

                                           =           349.7 x²    square units.
3 0
4 years ago
Read 2 more answers
ANSWER ASAP What is the value of a a-2=3+6a/3
hodyreva [135]

Answer:

try putting -5x I believe that's it

7 0
3 years ago
Which of the following could be the equation of the function below?<br><br> Timed, please hurry
oksano4ka [1.4K]
Try The 3rd one I know it’s right
8 0
3 years ago
Given f(x) = 17-x^2, what is the average rate of change in f(x) over the interval [1, 5]
pentagon [3]
Average rate of change  over [1,5]   = f(5) - f(1)  /  5 - 1

=  [(17-5^2) - (17-1) ] / 4

=  (-8 - 16)  /  4  = -24 / 4  = -6 Answer
3 0
4 years ago
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