Answer:
dy/dx = 6x(x²-3)cos2x - 2(x²-3)³sin2x
Step-by-step explanation:
We use the Product Rule:
y= (x²-3)³cos2x
dy/dx = (x²-3)³ d(cos2x)/dx + cos2x * d ((x²-3)³)/dx
= (x²-3)³ * -2sin2x + cos2x * 3(x²-3)*2x
= -2sin2x*(x²-3)³ + 6xcos2x*(x²-3)
= 6x(x²-3)cos2x - 2(x²-3)³sin2x
D-10 I think or it could be b
I found this for you. It even tells you how the answer was achieved.
<span>The general term for the sequence 2, 4, 6, 8, 10, . . . is 2n.</span>
A. Multiplied by 2 for the first then for the second multiply by three.
Explanation: the equations already have opposite signs for y so reversing the signs would be counterproductive. (Eliminates B and D) and the easiest way is to get the numbers before the Y variable to be the same. The top by 2 and bottom by 3 would do that, leaving only A.
