The mass of a watermelon is 1,940g more than the total mass of 8 similar peaches. If the total mass of the watermelon and

Please, I really need help-

posledela

<h3>Answer: 48</h3>

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Explanation:

Triangle ABC is isosceles because AC = BC.

The angles opposite these congruent sides are angle ABC and angle BAC. These are the base angles.

For any isosceles triangle, the base angles are congruent.

Angle BAC = 69 degrees is given. So angle ABC = 69 as well.

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The missing angle must add to the two other angles so that all three angles in a triangle add to 180

(angle ABC) + (angle BAC) + (angle BCA) = 180

69 + 69 + (angle BCA) = 180

138 + (angle BCA) = 180

angle BCA = 180-138

angle BCA = 42

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Angle DCE is congruent to angle BCA because they are vertical angles.

Triangle DCE is a right triangle. The missing angle is 90-(angle BCA) = 90-42 = 48

angle EDC = 48 degrees

6 0

4 years ago

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Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu

olchik [2.2K]

Answer:

a) $s^2 =30^2 =900$

b) $\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

c) $23.818 \leq \sigma \leq 41.112$

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in the variability in the number of rooms occupied per day during a particular season of the year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

$s^2 =30^2 =900$

Part b

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The degrees of freedom are given by:

$df=n-1=20-1=19$

Since the Confidence is 0.90 or 90%, the significance $\alpha=0.1$ and $\alpha/2 =0.05$ , the critical values for this case are:

$\chi^2_{\alpha/2}=30.144$

$\chi^2_{1- \alpha/2}=10.117$

And replacing into the formula for the interval we got:

$\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

Part c

Now we just take square root on both sides of the interval and we got:

$23.818 \leq \sigma \leq 41.112$

5 0

4 years ago

Please Help!!!!!! Using the rest of my points for this!

navik [9.2K]

It’s the first one on the top left corner

7 0

3 years ago

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The sum of all the interior angles in a triangle is blank degrees. Please HELP

ozzi

Answer:

180º

Step-by-step explanation:

All the interior angles add up to 180º degrees.

3 0

3 years ago

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Find the missing value. Show your work. Round to the nearest hundredth. SOMEONE PLEASE HELP ME W THIS ! ILL VOTE BRAINIEST ANSWE

Olenka [21]

Since the side which measures 10 is a vertical projection of the hipotenuse x on a 20 degree angle:

10 = x*sin(20°)

x = 29.238044

Since we have to round to the nearest hundreth:

x = 29.24 m

8 0

3 years ago

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