Find the Lateral area of a square pyramid with a slant height of 22m and a base length of 8m
1 answer:
Answer: 352
Step-by-step explanation:
To find the Lateral area of a square pyramid , we will follow the three steps below:
1. Find the perimeter of the base
2. Multiply the perimeter by the slant height
3. Divide the result above by 2
That is :
The lateral surface area of a regular pyramid is lateral area = perimeter of base x slant height of pyramid) ÷ 2.
Applying the formula above:
1. The base is a square , therefore the perimeter of a square is 4L , That is
Perimeter = 4(8)
Perimeter = 32m
2. Perimeter x slant height , that is
32 x 22 = 704m
3. Dividing the result by 2 , we have :
704/2 = 352
Therefore , the Lateral area of the pyramid is 352
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Answer:
A
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (0, 3) and (x₂, y₂ ) = (1, 1)
m = = - 2
note the line crosses the y- axis at (0, 3) ⇒ c = 3
y = - 2x + 3 → A