Find the Lateral area of a square pyramid with a slant height of 22m and a base length of 8m
1 answer:
Answer: 352
Step-by-step explanation:
To find the Lateral area of a square pyramid , we will follow the three steps below:
1. Find the perimeter of the base
2. Multiply the perimeter by the slant height
3. Divide the result above by 2
That is :
The lateral surface area of a regular pyramid is lateral area = perimeter of base x slant height of pyramid) ÷ 2.
Applying the formula above:
1. The base is a square , therefore the perimeter of a square is 4L , That is
Perimeter = 4(8)
Perimeter = 32m
2. Perimeter x slant height , that is
32 x 22 = 704m
3. Dividing the result by 2 , we have :
704/2 = 352
Therefore , the Lateral area of the pyramid is 352
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To simplify this, you would have to turn b^-2 into a positive exponent.
To do this, we have to flip b^-2, which would get rid of the negate from the exponent: -2
3a^4 b^-2 c^3 / b^-2
Then we get the answer:
3a^4 c^3
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b^-2
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To do this, we have to flip b^-2, which would get rid of the negate from the exponent: -2
3a^4 b^-2 c^3 / b^-2
Then we get the answer:
3a^4 c^3
------------
b^-2
I have a picture to clarify!
I hope this helped, let me know if you don't understand! ^.^