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N76 [4]
4 years ago
6

Which equations represent functions?

Mathematics
2 answers:
Alla [95]4 years ago
7 0
A is not a function. It is a sideways parabola.
B is a function. It is a line.
C is not a function
D is a function. It is a parabola.
ANSWER: B & D
garik1379 [7]4 years ago
4 0
Hello,
B, C, and D are the correct answers. Option D is the parent function of a parabola which is a function (it passes the vertical line test). Option C is also a parabola (shifted a unit to the right) and Option B is a linear graph which is a function. Option A doesn't pass the vertical line test and therefore isn't a function. I attached an image in case you weren't sure what the vertical line test is. Hope this helps!

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If ξ={1 , 2 , 3 , . . . , 8 , 9 , 10}
DENIUS [597]

Answer:

{1,4}

Step-by-step explanation:

A={3,6,9}

B={2,3,5,7}

C={1,2,3,4,5}

AUB={2,3,5,6,7,9}

(AUB)'={1,4,8,10}

(AUB)'⋂C={1,4}

7 0
3 years ago
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What is 10 times the quoitent of 104 and 8
sesenic [268]
10 * (104/8)

104/8 = 13

13*10 = 130

Answer: 130
6 0
3 years ago
Last winter Armand had StartFraction 5 Over 6 EndFraction of a row of stacked logs. At the end of the winter he had StartFractio
irina [24]

Answer:

3/10

Step-by-step explanation:

We have that the Armans last winter had 5/6 of a row of stacked logs and at the end of the winter he had 8/15 of the same row left, therefore:

Ambitious

First we have to do is that the denominator is the same.

in the case of 5/6 it would be 25/30

and for 8/15 it would be 16/30

Now if we can do the subtraction and it would be:

25/30 - 16/30 = 9/30 or what equals 3/10

3/10 was the amount of wood he burned in the winter

6 0
4 years ago
Triangle ADB is similar to Triangle EDC. Find CB.<br>​
ryzh [129]

Step-by-step explanation:

If triangles ADB and EDC are similar, then corresponding sides are proportional, from which we conclude:

BC/CD = AE/ED

BC / 21 = 6 / 18

Multiply by 21 on both sides,

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(note: Length BC is the same as length CB).

8 0
3 years ago
In the middle of a basketball court, the circle has a diameter of 5 feet. If
Sedbober [7]

Answer:

The distance that Mrs. Gilbertson's daughter walked was 188.4 feet

Step-by-step explanation:

Here we have that Mrs. Gilbertson's daughter walked round the circle 12 times where the diameter of the circle = 5 ft., therefore, the circumference of the circle, the distance walked round each of the 12 times = π·D

Where:

D = 5 ft

Hence, circumference = π × 5 = 3.14 × 5 = 15.7 ft

Therefore, by walking round the circle 12 times, the total distance that Mrs. Gilbertson's daughter walked = 12 × 15.7 = 188.4 ft.

5 0
4 years ago
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