Which equations represent functions?
2 answers:
Hello,
B, C, and D are the correct answers. Option D is the parent function of a parabola which is a function (it passes the vertical line test). Option C is also a parabola (shifted a unit to the right) and Option B is a linear graph which is a function. Option A doesn't pass the vertical line test and therefore isn't a function. I attached an image in case you weren't sure what the vertical line test is. Hope this helps!
B, C, and D are the correct answers. Option D is the parent function of a parabola which is a function (it passes the vertical line test). Option C is also a parabola (shifted a unit to the right) and Option B is a linear graph which is a function. Option A doesn't pass the vertical line test and therefore isn't a function. I attached an image in case you weren't sure what the vertical line test is. Hope this helps!
You might be interested in
Answer:
x≥
Step-by-step explanation:
given 1.5x+3.75≥5.5
→ 1.5x≥5.5-3.75
→ 1.5x≥1.75
→ x≥
→ x≥
Simplifying h(x) gives
h(x) = (x² - 3x - 4) / (x + 2)
h(x) = ((x² + 4x + 4) - 4x - 4 - 3x - 4) / (x + 2)
h(x) = ((x + 2)² - 7x - 8) / (x + 2)
h(x) = ((x + 2)² - 7 (x + 2) - 14 - 8) / (x + 2)
h(x) = ((x + 2)² - 7 (x + 2) - 22) / (x + 2)
h(x) = (x + 2) - 7 - 22/(x + 2)
h(x) = x - 5 - 22/(x + 2)
An oblique asymptote of h(x) is a linear function p(x) = ax + b such that
In the simplified form of h(x), taking the limit as x gets arbitrarily large, we obviously have -22/(x + 2) converging to 0, while x - 5 approaches either +∞ or -∞. If we let p(x) = x - 5, however, we do have h(x) - p(x) approaching 0. So the oblique asymptote is the line y = x - 5.
The point-slope form:
m - slope
(x₁, y₁) - point
The formula of a slope:
We have the points (-2, 7) and (1, 1). Substitute:
<em>point-slope form</em>
<em> slope-intercept form</em>
<em>standard form</em>