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2 years ago

F(x) = 3x + 7. What is f(4) ?

Mathematics

2 answers:

padilas [110]2 years ago

6 0

Answer:

I believe the answer is 19.

marshall27 [118]2 years ago

3 0

F(4) : 3(4) + 7
: 12 + 7
f(4) : 19

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Vertices A and B of triangle ABC are on one bank of a river, and vertex C is on the opposite bank. The distance between A and B

Anna71 [15]

Answer:

The length of side b is 179 ft

Step-by-step explanation:

Given triangle ABC in which

∠A = 33°, ∠B = 63°, c=200

we have to find the length of b

In ΔABC, by angle sum property of triangle

∠A+∠B+∠C=180°

33°+63°+∠C=180°

∠C=180°-33°-63°=84°

By sine law,

$\frac{\sin \angle A}{a}=\frac{\sin \angle B}{b}=\frac{\sin \angle C}{c}$

$\frac{\sin \angle B}{b}=\frac{\sin \angle C}{c}$

$\frac{\sin 63^{\circ}}{b}=\frac{\sin 84^{\circ}}{200}$

$b=200\times \frac{\sin 63^{\circ}}{\sin 84^{\circ}}=179.182887\sim 179 ft$

The length of side b is 179 ft

Option C is correct.

7 0

3 years ago

35,000 divided by 120

Naya [18.7K]

Answer:

291.666666667

Step-by-step explanation:

Rounds to 291.7

8 0

2 years ago

Read 2 more answers

A box contains 24 transistors,4 of which are defective. If 4 are sold at random,find the following probabilities. i. Exactly 2 a

zavuch27 [327]

SOLUTION

This is a binomial probability. For i, we will apply the Binomial probability formula

i. Exactly 2 are defective

Using the formula, we have

$\begin{gathered} P_x=^nC_x\left(p^x\right?\left(q^{n-x}\right) \\ Where\text{ } \\ P_x=binomial\text{ probability} \\ x=number\text{ of times for a specific outcome with n trials =2} \\ p=\text{ probability of success = }\frac{4}{24}=\frac{1}{6} \\ q=probability\text{ of failure =1-}\frac{1}{6}=\frac{5}{6} \\ ^nC_x=\text{ number of combinations = }^4C_2 \\ n=\text{ number of trials = 4} \end{gathered}$

Note that I made the probability of being defective as the probability of success = p

and probability of none defective as probability of failure = q

Exactly 2 are defective becomes the binomial probability

$\begin{gathered} P_x=^4C_2\times\lparen\frac{1}{6})^2\times\lparen\frac{5}{6})^{4-2} \\ P_x=6\times\frac{1}{36}\times\frac{25}{36} \\ P_x=\frac{25}{216} \\ =0.1157 \end{gathered}$

Hence the answer is 0.1157

(ii) None is defective becomes