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2 years ago

Just help don’t ask please

Mathematics

1 answer:

Vlad [161]2 years ago

4 0

Step-by-step explanation:

change graphic into alohabet so it is easier to see

solve easy equation with only a type of unknown first..

once you found the value of the unknownm , substitute it in any equation so you can find the value of other unknown.

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Solve the radical equation.<br> sqrt 25 – 40x = X – 10

Citrus2011 [14]

-40x=-10-20

-40x=-35

x= 7/8

5 0

2 years ago

Javier drove 45 miles. This represent 60% of his entire trip. What is the total number of miles in Javier’s trip

Andrews [41]

60% of trip = 45 miles

let total trip distance = l

60% is given by multiplying by 0.6

So;

0.6l = 45 \\ \\ l = \frac{45}{0.6} \\ \\ \boxed{l = 75}

Your answer is 75 miles

8 0

3 years ago

Read 2 more answers

A government report gives a 99% confidence interval for the proportion of welfare recipients who have been receiving welfare ben

juin [17]

Answer:

The estimation for the proportion for this case is $\hat p = 0.21$

And we know that the 99% confidence interval is given by:

$0.21 \pm 0.045$

So then the margin of error at 99% of confidence is 0.045, and the margin of error is given by this formula:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

If we decrease the confidence level this margin of error can't be higher than 0.045 so then the correct answer for this case would be:

d. 21% ± 4.8%

Because if the z value decrease from 2.58 to 1.96 not makes sense that the margin of error increase from 0.045(4.5%) to 0.048(4.8%)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

The estimation for the proportion for this case is $\hat p = 0.21$

And we know that the 99% confidence interval is given by:

$0.21 \pm 0.045$

So then the margin of error at 99% of confidence is 0.045, and the margin of error is given by this formula:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

If we decrease the confidence level this margin of error can't be higher than 0.045 so then the correct answer for this case would be:

d. 21% ± 4.8%

Because if the z value decrease from 2.58 to 1.96 not makes sense that the margin of error increase from 0.045(4.5%) to 0.048(4.8%)

5 0

3 years ago

I need help with question three

miss Akunina [59]

Hey there!

<u>-3 and 1 will both be farther to the right on the number line.</u>

On a number line, the farther right you go, the higher the values get.

Positive numbers are to the right of zero, with negative numbers to the left.

Since both -3 and 1 are larger than -7, they will be farther to the right.

Hope this helps!

3 0

3 years ago

20 POINTS - 1 EASY QUESTION

Vaselesa [24]

Answer and explanation:

Geometary software is merely a software implementation of solving the area of a triangle. Therefore geometry software employs all the methods used in coordinate algebra(manual) albeit behind the scenes, in the console of the software, and just displays the area in the screen after solving. While geometry software displays the area using automated methods in code, coordinate algebra solves area of the triangle manually using several steps. In both cases, we observe that algebra is required to solve area of the triangle as it is part of the algorithm used in the code for the geometry software. Also being able to use the geometry software requires that one understand coordinate algebra to be able to plot lines, points and planes at the correct locations on the screen and get desired result.

7 0

3 years ago