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Digiron [165]
3 years ago
12

Integral of 1/ (a+b-(a-b)x*) dx where (0

Mathematics
1 answer:
mylen [45]3 years ago
3 0
\displaystyle\int\frac{\mathrm dx}{a+b-(a-b)x}=\frac1{b-a}\int\frac{\mathrm dy}y

where y=a+b-(a-b)x\implies \mathrm dy=(b-a)\,\mathrm dx. Then

\displaystyle\frac1{b-a}\int\frac{\mathrm dy}y=\frac{\ln|y|}{b-a}+C
\displaystyle\int\frac{\mathrm dx}{a+b-(a-b)x}=\frac{\ln|a+b-(a-b)x|}{b-a}+C
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