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4 years ago

HELP I WILL MARK YOU AS A BRAINLIEST!!

Mathematics

1 answer:

Darina [25.2K]4 years ago

4 0

estimate - about 1.3

solve

just subtract 2.7 - 4 and that gives u 1.3

hope this helps tell me if u need help with anything else

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Is this right? 20 points if you help me PLEASE I NEED IT ASAP. CORRECT ME IF IM WRONG!!

Flauer [41]

Answer:

correct

Step-by-step explanation:

4 0

3 years ago

The price of a suit decreased from 280 to 182 during a clearance sale. What is the percent of decrease in the price?

Bogdan [553]

Answer:

35%

Step-by-step explanation:

the percent decrease is calculated using

percent decrease = $\frac{decrease}{originalprice}$ × 100%

decrease = 280 - 182 = 98

percent decrease = $\frac{98}{280}$ × 100% = 35%

3 0

3 years ago

Which expression represents the phrase "8 less than the product of 6 and a number ,x"?

elena55 [62]

6x-8
There is 8 less (so -8) than the product of 6 and x (so 6x).

5 0

4 years ago

Read 2 more answers

Richard and Teo have a combined age of 21. Richard is 3 years older than twice Teo’s age. How old are Richard and Teo?

SCORPION-xisa [38]

Answer:

Richard's age = 15

Teo's age = 6

Step-by-step explanation:

Let's say Teo's age is x.

Then, we will get this very equation.

$3 + 2x$

The equation above is Richard's age.

$x + 2x + 3 = 21$

This equation is their ages conbined.

Now, let's solve the equation.

Collect like terms.

$3x + 3 = 21$

Move the constant. ( Which is 3, in this case. )

$3x = 21 - 3$

Calculate.

$3x = 18$

Because we want only "x", divide both sides of the equation by 3.

$x = 6$

As I have said above, "x" is Teo's age.

Let's find Richard's.

It is:

2x + 3

x is 6.

(2 x 6) + 3

12 + 3

15 ( Richard's age.)

I hope it helps.

8 0

3 years ago

PLEASE HELP!!

cluponka [151]

Answer:

$x\in(-\infty,-2)\cup(5,\infty)$

Step-by-step explanation:

The duadratic function $g(x)=x^2+20$ begin to exceed the linear function $f(x)=3x+30$ when $g(x)>f(x)$

Solve this inequality:

$x^2+20>3x+30\\ \\x^2-3x+20-30>0\\ \\x^2-3x-10>0\\ \\x^2-5x+2x-10>0\\ \\x(x-5)+2(x-5)>0\\ \\(x-5)(x+2)>0$

This inequality is equivalent to

$\left[\begin{array}{l}\left\{\begin{array}{l}x-5>0\\x+2>0\end{array}\right.\\ \\\left\{\begin{array}{l}x-5-2\end{array}\right.\\ \\\left\{\begin{array}{l}x$

Answer: $x\in(-\infty,-2)\cup(5,\infty)$

8 0

3 years ago

Read 2 more answers