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Darya [45]
3 years ago
6

Which fraction equals 4?

Mathematics
1 answer:
Ilya [14]3 years ago
7 0

Answer: 8/2

Step-by-step explanation:

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The sum of the first and third consecutive add integers is 131 less than 3 times the second integer.Find the 3 integers.Pls writ
Arisa [49]
3 consecutive odd integers....x, x + 2, and x + 4

x + x + 4 = 3(x + 2) - 131
2x + 4 = 3x + 6 - 131
2x + 4 = 3x - 125
2x - 3x = - 125 - 4
-x = - 129
x = 129

x + 2 = 129 + 2 = 131
x + 4 = 129 + 4 = 133

so ur 3 odd numbers are : 129,131, and 133 <==
6 0
3 years ago
Consider a series system composed of 4 separate components where each component has a 30% chance of failing. Assume each compone
Marina86 [1]

Answer:

16.15% probability that exactly 3 of them would function

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Probability of each system working:

4 components, which means that n = 4

Each has a 30% probability of failing, so p = 1 - 0.3 = 0.7

For the system to work, all 4 components have to work. This is P(X = 4).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{4,4}.(0.7)^{4}.(0.3)^{0} = 0.2401

0.2401 probability of a system working.

If you have 7 of these systems, what is the probability that exactly 3 of them would function?

Now 7 systems, so n = 7

0.2401 probability of a system working.

We have to find P(X = 3).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{7,3}.(0.2401)^{3}.(0.7599)^{4} = 0.1615

16.15% probability that exactly 3 of them would function

5 0
3 years ago
The sum of two numbers is 14. When one number is added to twice the other number, the result is 25. Find the numbers
ELEN [110]

Let x and y be the two numbers. We have:

\begin{cases}x+y=14\\x+2y=25\end{cases}

Subtract the first equation from the second to get

y=11

And deduce

x+11=14 \iff x=3

The two numbers are 3 and 11.

5 0
3 years ago
2/5 × 6/7= simplify form​
kirill115 [55]

Answer:

2 x 6 = 12

5 x 7 = 35

12/35

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Translation, Rotation, and Reflection<br><br>Please help me
Firlakuza [10]

See the attached picture.

6 0
4 years ago
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