The equation of c is an illustration of subject of formula
The equation of c in terms of r and t is c = r - 15/t
<h3>How to determine the equation?</h3>
The equation is given as:
t = 15/(r - c)
Cross multiply
t(r - c) = 15
Divide both sides by t
r - c = 15/t
Subtract r from both sides
-c = -r + 15/t
Multiply both sides by -1
c = r - 15/t
Take LCM
Hence, the equation of c in terms of r and t is
Read more about subject of formula at:
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Complete options are;
A) Paired t-test for means
B) Paired Z-test for means
C) Z-test for proportion
D) t-test for means
E) Z-test for means
F) t-test for proportion
Answer:
B) Paired Z-test for means
Step-by-step explanation:
We are told that the distances travelled are normally distributed.
We are also trying to find out if the average distance travelled by the Titleist Pro V1 golf balls is farther than that of the Callaway Chrome Soft golf balls.
Also, the standard deviation of both cases are known.
Thus, this is where Paired Z-test for means is used.
Answer:
0.136m
Step-by-step explanation:
This is because if you draw a diagram, and label all the sides of the triangle (opp, hyp, adj), the adjacent angle is 3m. You can now use the sine rule to find the hypotenuse (length of ladder) by doing: cos 20= 3/h. You divide cos(20) by 3 and you get the answer of 0.13602m.
Lining up the trapezoids you need to notice that you have measurements for the LEFT side of both trapezoids. These measurements will be used to set up the ratio of small to large. 8/12 = 2/3 is the ratio of small trapezoid to large trapezoid.
To find a: 8/12 = 12/a; cross multiply; 8a = 144, divide both sides by 8; a = 18
To find b: 8/12 = b/6; cross multiply; 12b = 48, divide both sides by 12; b = 4
To find c: 8/12 =c/15; cross multiply; 12c =120, divide both sides by 12; c = 10
Instead of using 8/12 you could have used the reduced version, 2/3.
We can define the speed as the quotient between the distance moved, and the time it takes to move that distance, so we have:
<u>speed = Distance/Time.</u>
Now we can rewrite this as:
<u>Distance = Speed*Time.</u>
We will find that the speed of the car was 21 mi/h.
Here the information given is:
Mr. Pipkins speed is: S = 3.5 mi/h
The car needed 27 "steps" to reach the corner.
Mr. Pipkins needed 27 + 135 = 162 "steps" to reach the same corner.
Because the number of steps is related to time and distance, the ratio between the number of steps should be the same as the ratio between the speeds:
162/27 = 6
(Pipkins needed 6 tomes more steps than the car, so the car moves 6 times faster than Pipkins)
This means that the speed of the car is 6 times larger than the speed of Mr. Pipkins.
Then the speed of the car is:
S' = 6*(3.5 mi/h) = 21 mi/h.
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