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3 years ago

The equation of a line is y = {x+5.

Mathematics

1 answer:

Mariulka [41]3 years ago

4 0

Answer:

Sorry I did not know your answer

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Would appreciate the help!

Svetllana [295]

Two segments that are tangent to a circle from the same external point are of equal length.
9) 2x²=8x
2x²-8x=0
x(2x-8)=0
x=0,
2x-8=0
x=4 can be
2*4²=8*4=32

10) y=y²/7
y²/7- y=0
y(y/7 -1)=0
y=0,
y/7 - 1=0
y/7=1
y=7 can be
y=y²/7= 7

4 0

3 years ago

A baker's bread recipe calls for 3

xenn [34]

Answer: 6 cups
explanation: she has 1 cup measuring cup and has to fill it 3 times for each loaf 3*2=6

8 0

3 years ago

34:45:63 = x:90:126<br> What is x?

e-lub [12.9K]

Answer:

x = 68

Step-by-step explanation:

If you divided 90 by 45, you can see that the 1st ratio has been multiplied by 2 to get the second ratio. To get x, simply multiply 34 by 2 and you should get 68

4 0

3 years ago

Read 2 more answers

The second angle of a triangular kite is four times as large as the first. The third angle is 15 degrees more than the sum of th

frutty [35]

Let's set the first angle as x, the second angle is then 4x, and the third angle is (x+4x)+15, which is 5x+15
the three angles make a sum of 180: x+4x +5x+15=180
10x=165
x=16.5
the second angle is 4x=4*16.5=66

5 0

3 years ago

Mopeds (small motorcycles with an engine capacity below 50 cm3) are very popular in Europe because of their mobility, ease of op

Mashcka [7]

Answer:

a) P(X<50)=0.9827

b) P(X>47)=0.4321

c) P(-1.5<z<1.5)=0.8664

Step-by-step explanation:

We will calculate the probability based on a random sample of one moped out of the population, normally distributed with mean 46.7 and standard deviation 1.75.

a) This means we have to calculate P(x<50).

We will calculate the z-score and then calculate the probability accordign to the standard normal distribution:

$z=\dfrac{X-\mu}{\sigma}=\dfrac{50-46.7}{1.75}=\dfrac{3.7}{1.75}=2.114\\\\\\P(X$

b) We have to calculatee P(x>47).

We will calculate the z-score and then calculate the probability accordign to the standard normal distribution:

$z=\dfrac{X-\mu}{\sigma}=\dfrac{47-46.7}{1.75}=\dfrac{0.3}{1.75}=0.171\\\\\\P(X>47)=P(z>0.171)=0.4321$

c) If the value differs 1.5 standard deviations from the mean value, we have a z-score of z=1.5

$z=\dfrac{(\mu+1.5\sigma)-\mu}{\sigma}=\dfrac{1.5\sigma}{\sigma}=1.5$

So the probability that maximum speed differs from the mean value by at most 1.5 standard deviations is P(-1.5<z<1.5):

$P(-1.5$

3 0

3 years ago