BRAINIEST ANSWER it’s only 2 questions!! :))) (if you’re good at math please help)

A sphere has a radius of 6 meters. A second sphere has a radius of 3 meters. What is the difference of the volumes of the sphere

erica [24]

The volume of the first figure: 904.78 m^3
the volume of the second figure: 113.1 m^3
Difference: 904.78-113.1= 791.68

6 0

4 years ago

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Simplify the expression

Rudiy27

The answer is D, I'm 95% sure, double check just in case

6 0

3 years ago

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Which terms could be used as the last term of the expression below to create a polynomial written in standard form? Check all th

kogti [31]

A polynomial is said to be in standard form if it is written in the order of degree from highest to lowest from left to right.

The degree of a term of a polynomial is the exponent of the variable or the sum of the exponents of the variables of that term of the polynomial.

Thus, given the expression
$-5x^2y^4 + 9x^3y^3+\_\_\_$

$-5x^2y^4$ has a degree of 6, and
$9x^3y^3$ has a degree of 6.

Thus, the exponent of the variable or the sum of the exponents of the variables of the next term of the polynomial must be less than or equal to 6 for the polynomal to be said to be in standars form.

Therefore, the terms that could be used as the last term of the given expression to create a polynomial written in standard form are
$x^5, \\ \\ 
y^5, \\ \\ 
6x^4y, \ and \\ \\ 
-xy^5$

7 0

3 years ago

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A university wants to compare out-of-state applicants' mean SAT math scores (?1) to in-state applicants' mean SAT math scores (?

nordsb [41]

Answer:

d. Yes, because the confidence interval does not contain zero.

Step-by-step explanation:

We are given that the university looks at 35 in-state applicants and 35 out-of-state applicants. The mean SAT math score for in-state applicants was 540, with a standard deviation of 20.

The mean SAT math score for out-of-state applicants was 555, with a standard deviation of 25.

Firstly, the Pivotal quantity for 95% confidence interval for the difference between the population means is given by;

P.Q. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ ~ $t__n__1-_n__2-2$

where, $\bar X_1$ = sample mean SAT math score for in-state applicants = 540

$\bar X_2$ = sample mean SAT math score for out-of-state applicants = 555

$s_1$ = sample standard deviation for in-state applicants = 20

$s_2$ = sample standard deviation for out-of-state applicants = 25

$n_1$ = sample of in-state applicants = 35

$n_2$ = sample of out-of-state applicants = 35

Also, $s_p=\sqrt{\frac{(n_1-1)s_1^{2} +(n_2-1)s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(35-1)\times 20^{2} +(35-1)\times 25^{2} }{35+35-2} }$ = 22.64

Here for constructing 95% confidence interval we have used Two-sample t test statistics.

So, 95% confidence interval for the difference between population means ( $\mu_1-\mu_2$ ) is ;

P(-1.997 < $t_6_8$ < 1.997) = 0.95 {As the critical value of t at 68 degree

of freedom are -1.997 & 1.997 with P = 2.5%}

P(-1.997 < $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ < 1.997) = 0.95

P( $-1.997 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ < ${(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}$ < $1.997 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ ) = 0.95

P( $(\bar X_1-\bar X_2)-1.997 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ < ( $\mu_1-\mu_2$ ) < $(\bar X_1-\bar X_2)+1.997 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ ) = 0.95

95% confidence interval for ( $\mu_1-\mu_2$ ) =

[ $(\bar X_1-\bar X_2)-1.997 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ , $(\bar X_1-\bar X_2)+1.997 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ ]

=[ $(540-555)-1.997 \times {22.64 \times \sqrt{\frac{1}{35} +\frac{1}{35} } }$ , $(540-555)+1.997 \times {22.64 \times \sqrt{\frac{1}{35} +\frac{1}{35} } }$ ]

= [-25.81 , -4.19]

Therefore, 95% confidence interval for the difference between population means SAT math score for in-state and out-of-state applicants is [-25.81 , -4.19].

This means that the mean SAT math scores for in-state students and out-of-state students differ because the confidence interval does not contain zero.

So, option d is correct as Yes, because the confidence interval does not contain zero.

6 0

3 years ago

34+x=54 koji je rezultat od x

IgorLugansk [536]

~Hello There!~

34 + x = 54
x = 54 - 34
x = 20

Hope This Helps You!
Good Luck :)
Have A Great Day ^_^

- Hannah ❤

7 0

3 years ago

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