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Ivahew [28]
3 years ago
11

Please help me. This is due today

Mathematics
1 answer:
sattari [20]3 years ago
3 0

Answer:

it answer is 3 because it is trigonometry

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Calculate the value of 3a – 4b + 6c – 3d, when <br> a = 5 b = 4 c = 3 d = 2
Ne4ueva [31]

Answer:

3a – 4b + 6c – 3d

when a = 5 b = 4 c = 3 d = 2

the value

= 3×5 - 4×4 + 6×3 - 3×2

=15-16+18-6

=11

3 0
2 years ago
Which polynomial is a difference of two squares? <br> x2 − 16 <br> x2 + 16 <br> x2 − 8 <br> x2 + 8
AnnZ [28]
X2 - 16, is the answer. The first one.

x^2 - 16 = (x)^2 - 4^2, difference of two squares :)
8 0
4 years ago
Read 2 more answers
Find the Surface area of the attached image and round answer to the nearest tenth, if necessary.
Ilia_Sergeevich [38]

Answer:

150 m²

Step-by-step explanation:

area of triangle is 1/2(6)(9.5) = 28.5

there are 4 triangles

28.5 x 4 = 114

bottom is 6 x 6 = 36

114 + 36 = 150 m²

7 0
3 years ago
It is desired to compare the hourly rate of an entry-level job in two fast-food chains. Eight locations for each chain are rando
notka56 [123]

Answer:

It can be concluded that at 5% significance level that there is no difference in the amount paid by chain A and chain B for the job under consideration

Step by Step Solution:

The given data are;

Chain A 4.25, 4.75, 3.80, 4.50, 3.90, 5.00, 4.00, 3.80

Chain B 4.60, 4.65, 3.85, 4.00, 4.80, 4.00, 4.50, 3.65

Using the functions of Microsoft Excel, we get;

The mean hourly rate for fast-food Chain A, \overline x_1 = 4.25

The standard deviation hourly rate for fast-food Chain A, s₁ = 0.457478

The mean hourly rate for fast-food Chain B, \overline x_2 = 4.25625

The standard deviation hourly rate for fast-food Chain B, s₂ = 0.429649

The significance level, α = 5%

The null hypothesis, H₀:  \overline x_1 = \overline x_2

The alternative hypothesis, Hₐ:  \overline x_1 ≠ \overline x_2

The pooled variance, S_p^2, is given as follows;

S_p^2 = \dfrac{s_1^2 \cdot (n_1 - 1) + s_2^2\cdot (n_2-1)}{(n_1 - 1)+ (n_2 -1)}

Therefore, we have;

S_p^2 = \dfrac{0.457478^2 \cdot (8 - 1) + 0.429649^2\cdot (8-1)}{(8 - 1)+ (8 -1)} \approx 0.19682

The test statistic is given as follows;

t=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{S_{p}^{2} \cdot \left(\dfrac{1 }{n_{1}}+\dfrac{1}{n_{2}}\right)}}

Therefore, we have;

t=\dfrac{(4.25-4.25625)}{\sqrt{0.19682 \times \left(\dfrac{1 }{8}+\dfrac{1}{8}\right)}} \approx -0.028176

The degrees of freedom, df = n₁ + n₂ - 2 = 8 + 8 - 2 = 14

At 5% significance level, the critical t = 2.145

Therefore, given that the absolute value of the test statistic is less than the critical 't', we fail to reject the null hypothesis and it can be concluded that at 5% significance level that chain A pays the same as chain B for the job under consideration

3 0
3 years ago
Tanner is picking three varieties of apples at an orchard: Gala, Fuji, and Jazz. Each type of apple has a different cost per pou
Makovka662 [10]

Answer:

2g + 2f = 5.16

7g + 9f = 21.24

Step-by-step explanation:

Let

Gala = g ; Fuji = f ; jazz = j

g + f + j = 5.16 - - - (1)

j = g + f - - - (2)

From (1):

g + f + g + f = 5.16

2g + 2f = 5.16 - - - (3)

Total pound picked by Tanner = 12

3 Pounds of g ; 5 pounds of f

j = 12 - (5 +3) = 4 pounds

3g + 5f + 4j = 21.24 - - - (4)

3g + 5f + 4(g + f) = 21.24

3g + 5f + 4g + 4f = 21.24

7g + 9f = 21.24 - - - - - (5)

6 0
3 years ago
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