All categories

3 years ago

Light shines through window what is the area of a trapezoid shaped region created by the light

Mathematics

1 answer:

bogdanovich [222]3 years ago

5 0

Answer:

16 ft²

Step-by-step explanation:

The complete question is attached.

A trapezoid is a quadrilateral (has four sides) with one a parallel base. The base angles and the diagonals of an isosceles trapezoid are equal.

The area of a trapezoid = [(sum of the parallel bases) / 2] * height of the trapezoid.

Given that the parallel bases are 3 ft and 5 ft, while the height of the trapezoid is 4 ft. Hence:

The area of a trapezoid = [(3 + 5)/2] * 4

The area of a trapezoid = 16 ft²

You might be interested in

Two pillars have been delivered for the support of a shade structure in the backyard. they are both ten feet tall and the cross

BartSMP [9]

The steps to determine whether the pillars have the same volume are;

First, we must know that the volume of an object of uniform surface area is the product of its Area and height.

The uniform area of each pillar is then evaluated and if equal;

Both pillars can be concluded to have the same volume.

We must first recall that for various shapes, the volume of the shape is a function of its height.

For example: a A cylinderical pillar and a rectangular prism pillar;

Volume of a cylinder = πr²h

Volume of a Cuboid = l × w × h

Since h = h.

Therefore, for both pillars to have the same volume; their Areas must be equal.

πr² = l × w

Learn more about Area and volume here

brainly.com/question/987829

#SPJ4

3 0

2 years ago

Lim (n/3n-1)^(n-1) n → ∞

n200080 [17]

Looks like the given limit is

$\displaystyle \lim_{n\to\infty} \left(\frac n{3n-1}\right)^{n-1}$

With some simple algebra, we can rewrite

$\dfrac n{3n-1} = \dfrac13 \cdot \dfrac n{n-9} = \dfrac13 \cdot \dfrac{(n-9)+9}{n-9} = \dfrac13 \cdot \left(1 + \dfrac9{n-9}\right)$

then distribute the limit over the product,

$\displaystyle \lim_{n\to\infty} \left(\frac n{3n-1}\right)^{n-1} = \lim_{n\to\infty}\left(\dfrac13\right)^{n-1} \cdot \lim_{n\to\infty}\left(1+\dfrac9{n-9}\right)^{n-1}$

The first limit is 0, since 1/3ⁿ is a positive, decreasing sequence. But before claiming the overall limit is also 0, we need to show that the second limit is also finite.

For the second limit, recall the definition of the constant, e :

$\displaystyle e = \lim_{n\to\infty} \left(1+\frac1n\right)^n$

To make our limit resemble this one more closely, make a substitution; replace 9/(n - 9) with 1/m, so that

$\dfrac{9}{n-9} = \dfrac1m \implies 9m = n-9 \implies 9m+8 = n-1$

From the relation 9m = n - 9, we see that m also approaches infinity as n approaches infinity. So, the second limit is rewritten as

$\displaystyle\lim_{n\to\infty}\left(1+\dfrac9{n-9}\right)^{n-1} = \lim_{m\to\infty}\left(1+\dfrac1m\right)^{9m+8}$

Now we apply some more properties of multiplication and limits:

$\displaystyle \lim_{m\to\infty}\left(1+\dfrac1m\right)^{9m+8} = \lim_{m\to\infty}\left(1+\dfrac1m\right)^{9m} \cdot \lim_{m\to\infty}\left(1+\dfrac1m\right)^8 \\\\ = \lim_{m\to\infty}\left(\left(1+\dfrac1m\right)^m\right)^9 \cdot \left(\lim_{m\to\infty}\left(1+\dfrac1m\right)\right)^8 \\\\ = \left(\lim_{m\to\infty}\left(1+\dfrac1m\right)^m\right)^9 \cdot \left(\lim_{m\to\infty}\left(1+\dfrac1m\right)\right)^8 \\\\ = e^9 \cdot 1^8 = e^9$

So, the overall limit is indeed 0:

$\displaystyle \lim_{n\to\infty} \left(\frac n{3n-1}\right)^{n-1} = \underbrace{\lim_{n\to\infty}\left(\dfrac13\right)^{n-1}}_0 \cdot \underbrace{\lim_{n\to\infty}\left(1+\dfrac9{n-9}\right)^{n-1}}_{e^9} = \boxed{0}$

7 0

3 years ago

I need help with 3 and 4 :))

igomit [66]

Ah so your confused? I got you fam let me explain. So it would be best to start in the middle then graph the coordinates, move those coordinates 6 right then 5 up for the first one. Then do the same thing for the other but move them 8 left and down once.

4 0

3 years ago

Read 2 more answers

Anuta_ua [19.1K]

Lets say you have 5 apples, but the you give away 3 of them.
To work how many you have left you take away.
5-3 = 2

Lets apply this with fractions now.
You have 9/7 yard, but then you give away 7/20 yard.
Now you take them away:
9/7 minus 7/20 = 131/140

Hope this helps :)

8 0

3 years ago

What is the rate in feet per second? 10 feet 16 seconds

Ierofanga [76]

Feet
_____
second

10 feet
________
16 second

equals

.625 feet per second

7 0

3 years ago