Given - Taisha has a general goal is to burn the 280 calories.
she is varies by the 25 calories.
Find out the maximum and minimum of calories burn by the taisha.
To proof -
let us assume that the calories burn by the taisha be x.
as given the calories are varies by the 25 calories.
then the maximum calories equation becomes
x-25 = 280
x = 280 + 25
x = 305
the maximum calories burn by the taisha is 305 calories.
minimum calories equationbecomes
x + 25 = 280
x = 255
The minmum calories burn by the taisha is 255 calories.
Hence proved
<span>x-intercept, y = 0:
-2x + 8 =0
-2x = -8
x= -8/-2 = 4<span>
y-intercept, x =0
y = 8</span></span>
3 [ (20-4) / 2 ]= 3 * 16/2= 3 x 8 =24
5,(9)=5 9/9= 54/9=6
6/8/4= 6/2=3
Exact form = 7/3
Decimal = 2.3
Mixed number Form = 2 1/3
So... 4 folks, working for 8hours per day, do it in 15days
hmm alrite...so 4 folks working for 8hrs in 1 day, each one does 8, 4 of them, 4*8 = 32, so, they do 32 workhours every day, now for 15 days, that'd be 32*15, or 480
so, the whole job really takes 480 hours
now hmm let's see, the firm decides to increase the folks, but decrease the hours, so, 5 folks each working 6hours every day
how many workhours total? well 5*6 = 30
each is working 6hrs, 5 of them, so 30 workhours
how long will it take them if they only do 30 workhours everyday?
well the whole job is 480hours