Answer:
The velocity of the car after the collision is -5.36 m/s
Step-by-step explanation:
An elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies remains the same.
let the following:
m₁ = mass of the car = 1400 kg
m₂ = mass of the truck = 3200 kg
u₁ = velocity of the car before collision = 13.7 m/s
u₂ = velocity of the truck before collision = 0 m/s
v₁ = velocity of the car after collision
v₂ = velocity of the truck after collision
v₁ = [ u₁ * (m₁ - m₂) + u₂ * 2m₂ ]/ (m₁ + m₂)
= [ 13.7 * (1400 - 3200) + 0 * 2 * 3200 ]/ (1400 + 3200)
= - 5.36 m/s
So, <u>the velocity of the car after the collision is -5.36 m/s</u>
and surely you'd know what the roots are
Answer:
256π/3 cm³
Step-by-step explanation:
d = 2r => r = d/2 = 4cm/2 = 2 cm
V(sphere) = 4π·r³/3
= 4π·64/3 cm³
= 256π/3 cm³
I would say B because it only makes since, colleges are looking for whats better in students and you will also work in groups also. So i would go with B :)
