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Leokris [45]
3 years ago
9

Help khan academy!!!!

Mathematics
2 answers:
Anastaziya [24]3 years ago
6 0

Answer:

I have khan academy

what grade is this

and subject

Svetradugi [14.3K]3 years ago
5 0
She earns $1.2 per chore
She has $3
She wants to earn 13.50

Therefore, the inequality

1.2c + 3 is greater than or equal to 13.50
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Help me please nobody seems to help me :(
podryga [215]

Answer:

A: (4, -2)

B: (-3, -3)

C: (-2, 5)

D: (-3, -3)

E: (1, -4)

F: (0, 3)

6. Option B

Step-by-step explanation:

5 0
3 years ago
V2+4v-21=0 (solve by factoring)​
frozen [14]

Answer: (v + 7)(v -3)

Step-by-step explanation:

(v +7)(v -3)

v x v = v^2

v x -3 = -3v

7 x v = 7v

7 x -3 = -21

v^2 -3v +7v -21 = v^2 +4v -21 = 0

6 0
3 years ago
Read 2 more answers
Give me some ways to make 7,502
Komok [63]
7,000+500+2
2(3751)
7x10^3+5x10^2+2X10^0
5(1500.4)

8 0
3 years ago
Read 2 more answers
Which of these expressions is equivalent to -2(x-5)?
Serga [27]

Answer:

The answer is -2x+10

Step-by-step explanation:

Hope this helps

4 0
3 years ago
Evaluate the function f(x) at the given numbers (correct to six decimal places). F(x) = x2 − 5x x2 − x − 20 , x = 5.5, 5.1, 5.05
exis [7]

we are given

f(x)=\frac{x^2-5x}{x^2-x-20}

Firstly, we will simplify it

f(x)=\frac{x(x-5)}{(x-5)(x+4)}

f(x)=\frac{x}{(x+4)}

At x=5.5:

we can plug x=5.5

f(5.5)=\frac{5.5}{(5.5+4)}

f(5.5)=0.578947

At x=5.1:

we can plug x=5.1

f(5.1)=\frac{5.1}{(5.1+4)}

f(5.1)=0.56043956

At x=5.05:

we can plug x=5.05

f(5.05)=\frac{5.05}{(5.05+4)}

f(5.05)=0.558011

At x=5.01:

we can plug x=5.01

f(5.01)=\frac{5.01}{(5.01+4)}

f(5.01)=0.5560488

At x=5.005:

we can plug x=5.005

f(5.005)=\frac{5.005}{(5.005+4)}

f(5.005)=0.5558023

At x=5.001:

we can plug x=5.001

f(5.001)=\frac{5.001}{(5.001+4)}

f(5.001)=0.5556049

At x=4.9:

we can plug x=4.9

f(4.9)=\frac{4.9}{(4.9+4)}

f(4.9)=0.5505617

At x=4.95:

we can plug x=4.95

f(4.95)=\frac{4.95}{(4.95+4)}

f(4.95)=0.5530726

At x=4.99:

we can plug x=4.99

f(4.99)=\frac{4.99}{(4.99+4)}

f(4.99)=0.55506117

At x=4.995:

we can plug x=4.995

f(4.995)=\frac{4.995}{(4.995+4)}

f(4.995)=0.55503085

At x=4.999:

we can plug x=4.999

f(4.999)=\frac{4.999}{(4.999+4)}

f(4.999)=0.55550616



7 0
4 years ago
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