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mr Goodwill [35]
2 years ago
10

If sin A = 8/17 and tan B = 40/9 and angles A and B are in Quadrant I, find the value of * tan(A + B) .

Mathematics
1 answer:
nirvana33 [79]2 years ago
3 0

Step-by-step explanation:

tanA=8/15 and tan B=40/9

tan(A+B)=(tanA+tanB)/1-tanAtanB

(8/15+40/9)/1-(8/15×40/9)

=-672/185

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Zen deposited some money in a savings account. The graph below shows the value of Zen's investment y, in dollars, after x months
kifflom [539]

The y-intercept of 1000 in the graph is at the point where x is equal to 0.

At x=0, it means no month have passed. It is the initial point where Zen deposited the money.

What is the amount (y axis)? 1000!

So y represents the initial deposit of Zen, which is 1000.


ANSWER: Answer choice D (Amount of money Zen deposited in the savings account)

6 0
3 years ago
Read 2 more answers
Si en 11 cajas de chocolates hay 220 chocolates en total. Calcula cuántos chocolates habrá en total en 5 cajas de chocolates.
pochemuha

Answer:

Habrá 100 chocolates en total en 5 cajas de chocolates.

Step-by-step explanation:

Esta pregunta es resolvida usando proporciones, con lo uso de regla de tres .

11 cajas, 220 chocolates:

Entonces:

\frac{220}{11} = 20

20 chocolates por caja.

Calcula cuántos chocolates habrá en total en 5 cajas de chocolates.

20 chocolates por caja, entonces:

5*20 = 100

Habrá 100 chocolates en total en 5 cajas de chocolates.

6 0
2 years ago
I need help with this quickly
mixas84 [53]

Answer:

1.25y=x

Step-by-step explanation:

If A (or y)=5 and B (or x)=4 then I think the equation will be 1.25y=x

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7 0
3 years ago
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Name Score Julia 650 Andrew 550 Jason 380 Cathy 720 Jessica 710 Robert 550 The table gives the scores of 6 students from a class
Afina-wow [57]
3560/6 which is 593.3 I believe.
6 0
3 years ago
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Three balls are packaged in a cylindrical container as shown below. The balls just touch the top, bottom, and the sides of the c
lord [1]

Answer:

a. 5177 cm³

b. 3,451 cm³

c. 67%

Step-by-step explanation:

Given:

Diameter of each ball (d) = 13 cm

Radius of the ball (r) = radius of the cylinder = ½(13) = 6.5 cm

Height of the cylinder (h) = the sum of the diameters of the 3 balls = 3(13) = 39 cm

a. Volume of cylinder = πr²h

Plug in the values

Volume of cylinder = π*6.5²*39 = 5176.56 ≈ 5177 cm³

b. Total volume of the three balls = 3(volume of 1 ball) = 3(volume of sphere) = 3(⁴/3πr³)

Plug in the value

Total volume of the 3 balls = 3(⁴/3*π*6.5³) = 3(1150.35) = 3,451.05 ≈ 3,451 cm³

c. % of volume of the container occupied by the 3 balls = total volume of the three balls / volume of cylinder × 100

Plug in the values

= 3,451/5177 × 100

= 66.6602279

≈ 67%

6 0
3 years ago
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