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2 years ago

Challenger Elementary School has 800 students. Every Wednesday, 12 percent of the students stay after school for Chess Club.

2 answers:

8 0

Let's set up a proportion.

$\frac{x}{800} \frac{12}{100}$

Then solve for x:
12 x 800 = 9600
9600/100 = 96

96 is 12% of the 800 students. :)

Hope this helped! If you have anymore questions or don't understand, please comment or DM me. :)

V125BC [204]2 years ago

3 0

First you will need to set up your equation. Your 800 students is equal to 100% and x is equal to your 12%. Your equation should be set up similarly:

x 12
___ = ___
800 100

Next you will cross multiply. You will multiply x with 100 and 12 with 800.

100 * x = 12 * 800
100x = 9,600

Finally, you will make x equivalent to 1. You do this by dividing both sides of the equation by 100.

100x = 9,600
/ 100 /100
x = 96

If you have done your equation properly then your answer should come out to 96 students.

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"a pollster wishes to estimate the number of left-handed scientists. how large of a sample is needed in order to be 98% confiden

nadezda [96]

The sample size should be 250.

Our margin of error is 4%, or 0.04. We use the formula

$\text{ME}=z\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}$

To find the z-score:
Convert 98% to a decimal: 0.98
Subtract from 1: 1-0.98 = 0.02
Divide both sides by 2: 0.02/2 = 0.01
Subtract from 1: 1-0.01 = 0.99

Using a z-table (http://www.z-table.com) we see that this value has a z-score of approximately 2.33. Using this, our margin of error and our proportion, we have:

$0.04=2.33\sqrt{\frac{0.08(1-0.08)}{n}}
\\
\\0.04=2.33\sqrt{\frac{0.08(0.92)}{n}}$

Divide both sides by 2.33:
$\frac{0.04}{2.33}=\sqrt{\frac{0.08(0.92)}{n}}$

Square both sides:
$(\frac{0.04}{2.33})^2=\frac{0.08(0.92)}{n}$

Multiply both sides by n:
$(\frac{0.04}{2.33})^2n=0.08(0.92)$

Divide both sides to isolate n:
$\frac{0.08(0.92)}{(\frac{0.04}{2.33})^2}=n
\\
\\249.73=n
\\n\approx 250$

4 0

3 years ago

This is hard can someone help ?

Anastaziya [24]

6. Often, judging the symmetry and skewness of such distributions is not easy to do by eye, especially when they are asymmetrical or skewed in different ways. Here, the mean of set A is about 7, so the data is skewed to the left more than for set B, which has a mean of about 5.4--closer to the middle of the range.

Both data sets have the same range: 2–10. Set A's mode of 8 is higher than set B's mode of 6.

Hence, the only true statement appears to be

... B. Set B has the lesser mean.

7. For each of the 3 choices of meat, there are 3 choices of bread, and for each of any of those 9 choices, there are 4 choices of condiment—a total of 3×3×4 = 36 choices in all. The best answer is ...

... C. 36

8. The pie chart tells you 5% of the $4800 of monthly income is spent on transportation. That amount is .05×$4800 = ...

... C. $240

6 0

3 years ago

Can someone help me please

Lorico [155]

29 3/4 i am pretty sure !

4 0

2 years ago

Read 2 more answers

This is a question I have been trying to do for quite a while. My additional mathematics exam is next week and I need help. Anyo

Radda [10]

First of all, let's consider the line, since it's simpler to graph: we draw the endpoints and connect them:

$f(x)=2-\dfrac{3x}{4\pi} \implies f(0)=2,\quad f(2\pi)=\dfrac{1}{2}$

So, you just need to draw the points

$(0,2),\quad \left(2\pi, \dfrac{1}{2}\right)$

As for the trigonometric function, we have to start from the parent function $y=\sin(x)$ and derive the graph of its child function via transformations:

When we multiply the whole function by 2, we stretch the graph vertically. So, the function has still period $2\pi$ , but now it ranges from -2 to 2 instead of from -1 to 1 (amplitude 2)
When we multiply the argument by 2, we compress the function horizontally. So, the new period becomes $\pi$ , and the function makes two complete oscillations from 0 to $2\pi$

You can see the two functions in the image below. You can also see that the two graphs cross 4 times, meaning that the equation

$y_1=y_2$ has four solutions.

3 0

3 years ago

I spent 3/4 of my money and then I spent 1/5 of what was left.

olga nikolaevna [1]

3/4+1/5 would be 19/20

5 0

3 years ago