The sample size should be 250.
Our margin of error is 4%, or 0.04. We use the formula

To find the z-score:
Convert 98% to a decimal: 0.98
Subtract from 1: 1-0.98 = 0.02
Divide both sides by 2: 0.02/2 = 0.01
Subtract from 1: 1-0.01 = 0.99
Using a z-table (http://www.z-table.com) we see that this value has a z-score of approximately 2.33. Using this, our margin of error and our proportion, we have:

Divide both sides by 2.33:

Square both sides:

Multiply both sides by n:

Divide both sides to isolate n:
6. Often, judging the symmetry and skewness of such distributions is not easy to do by eye, especially when they are asymmetrical or skewed in different ways. Here, the mean of set A is about 7, so the data is skewed to the left more than for set B, which has a mean of about 5.4--closer to the middle of the range.
Both data sets have the same range: 2–10. Set A's mode of 8 is higher than set B's mode of 6.
Hence, the only true statement appears to be
... B. Set B has the lesser mean.
7. For each of the 3 choices of meat, there are 3 choices of bread, and for each of any of those 9 choices, there are 4 choices of condiment—a total of 3×3×4 = 36 choices in all. The best answer is ...
... C. 36
8. The pie chart tells you 5% of the $4800 of monthly income is spent on transportation. That amount is .05×$4800 = ...
... C. $240
29 3/4 i am pretty sure !
First of all, let's consider the line, since it's simpler to graph: we draw the endpoints and connect them:

So, you just need to draw the points

As for the trigonometric function, we have to start from the parent function
and derive the graph of its child function via transformations:
- When we multiply the whole function by 2, we stretch the graph vertically. So, the function has still period
, but now it ranges from -2 to 2 instead of from -1 to 1 (amplitude 2) - When we multiply the argument by 2, we compress the function horizontally. So, the new period becomes
, and the function makes two complete oscillations from 0 to 
You can see the two functions in the image below. You can also see that the two graphs cross 4 times, meaning that the equation
has four solutions.