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nikklg [1K]
1 year ago
14

The table shows the temperature (V) as different altitudes of). This is a linear relationship was the 0.00468 te dele The temper

ature at an altitude of 5,000 feet
Mathematics
1 answer:
polet [3.4K]1 year ago
6 0
\begin{gathered} \text{the general straight line equation is} \\ y=mx+b \\ \text{where m is the slope and b the y-intecept} \\ b\text{ can be obtained easily when x=0, because} \\ y=m(0)+b\Rightarrow y=b \\  \\ In\text{ this case, we can s}e\text{ that, when x=0} \\ y=69 \\ \text{hence b=69} \end{gathered}maybeyoumustwritethetemperaturesymbol\text{can you s}ee\text{ this message?}\text{may be you must write the temperature symbol "F". because this answer is correct.}\text{its very strange, its the only answer for linear behavior}

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Write an equation of the line that passes through the given point and is (a) parallel and (b)
viktelen [127]

Answer:

parallel line: y=-3x+14

perpendicular line: y=1/3x +2/3

Step-by-step explanation:

For the parallel line, use the point-slope formula to find the equation of the parallel line (since the slope is the same as the given line and the point (4,2) is given. For the perpendicular line, use the opposite reciprocal of the slope of the given line and use the point-slope formula again. The point-slope formula is Y-Y1=m(X-X1)

3 0
2 years ago
Can some one please explain how to do this? 1.253 x 7.4 =
drek231 [11]

Answer:

9.2722

Step-by-step explanation:

7.400

*1.252

_____

9.2722

Its simple, plz rate 5 str, thx, and brailiest

3 0
3 years ago
The endpoints of line RS are R(1, -3) and S(4,2). Find RS
laila [671]

Answer:

Part 1) RS=\sqrt{34}\ units

Part 2) CD=\sqrt{125}\ units

Part 3) The coordinates of endpoint C are (13,5)

Step-by-step explanation:

Part 1) The endpoints of line RS are R(1, -3) and S(4,2). Find RS

we now that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

substitute the values

RS=\sqrt{(2+3)^{2}+(4-1)^{2}}

RS=\sqrt{(5)^{2}+(3)^{2}}

RS=\sqrt{34}\ units

Part 2) The endpoints of line CD are C(-8,-1) and D(2,4). Find CD

we now that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

substitute the values

CD=\sqrt{(4+1)^{2}+(2+8)^{2}}

CD=\sqrt{(5)^{2}+(10)^{2}}

CD=\sqrt{125}\ units

Part 3) The midpoint of line AC is M(5,6). One endpoint is A(-3,7). Find the coordinates of endpoint C

The formula to calculate the midpoint between two points is equal to

M=(\frac{x1+x2}{2},\frac{y1+y2}{2})

Let

(x2,y2)-------> the coordinates of point C

(x1,y1) -------> the coordinates of point A

substitute the given values

(5,6)=(\frac{-3+x2}{2},\frac{7+y2}{2})

write the equations

\frac{-3+x2}{2}=5\\ \\-3+x2=10\\ \\ x2=10+3\\ \\x2=13

\frac{7+y2}{2}=6\\\\ 7+y2=12\\ \\ y2=12-7\\ \\y2=5

therefore

The coordinates of endpoint C are (13,5)

7 0
3 years ago
Image B is a dilation of image A true or false
storchak [24]

Please provide us with an attachment of image A and B so we can answer your question correctly.

7 0
3 years ago
Help me plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz
shtirl [24]

Answer:

-502.5

Step-by-step explanation:

The submarine is 502.5 feet below sea level initially. Since -502.5 is an integer, we can assume its a rational number. Sorry if I didn't properly answer the question in advance.

5 0
3 years ago
Read 2 more answers
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