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Nadya [2.5K]
1 year ago
6

Part 2 - Find the error(s) and solve the problem correctly.

Mathematics
1 answer:
JulijaS [17]1 year ago
3 0

The problem solved correctly as a single logarithm is log_{a} 2x^{3}/y^{2}

<h3>Simplifying Logarithm</h3>

From the question, we are to simplify the given logarithm

The given logarithm is

log_{a} 2x \ + \  2(log_{a} x -log_{a} y)

From the subtraction law of logarithm, we have that

log_{c} a -log_{c} b = log_{c} (a/b)

Thus,

The error in the solution was instead of multiplying, a was supposed to be divided by b

The correct solution is

log_{a} 2x \ + \  2(log_{a} x -log_{a} y)

log_{a} 2x \ + \  2(log_{a} (x/y) )

log_{a} 2x \ + \  log_{a} (x/y)^{2}

log_{a} 2x \ + \  log_{a} (x^{2}/y^{2})

Simplifying further

log_{a} 2x  \times (x^{2}/y^{2})

log_{a} 2x  \times x^{2}/y^{2}

log_{a} 2x^{3}/y^{2}

Hence, the problem solved correctly as a single logarithm is log_{a} 2x^{3}/y^{2}

Learn more on Simplifying logarithms here: brainly.com/question/247340

#SPJ1

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A null hypothesis is that the mean nose lengths of men and women are the same. The alternative hypothesis is that men have a lon
algol [13]

Answer:

b. There is not enough evidence to say that the populations of men and women have different mean nose lengths.

See explanation below.

Step-by-step explanation:

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the means for the two groups are different (men have longer mean nose length than women), the system of hypothesis would be:

Null hypothesis:\mu_{men} \leq \mu_{women}

Alternative hypothesis:\mu_{men} > \mu_{women}

Assuming that we know the population deviations for each group, for this case is better apply a z test to compare means, and the statistic is given by:

z=\frac{\bar X_{men}-\bar X_{women}}{\sqrt{\frac{\sigma^2_{men}}{n_{men}}+\frac{\sigma^2_{women}}{n_{women}}}} (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Let's assume that the calculated statistic is z_{calc}

Since is a right tailed test test the p value would be:

p_v =P(Z>z_{calc})=0.225

And we know that the p value is 0.225. If we select a significance level for example 0.05 or 0.1 we see that p_v >\alpha

And on this case we have enough evidence to FAIl to reject the null hypothesis that the means are equal. So then the best conclusion would be:

b. There is not enough evidence to say that the populations of men and women have different mean nose lengths.

8 0
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