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Nadya [2.5K]
2 years ago
6

Part 2 - Find the error(s) and solve the problem correctly.

Mathematics
1 answer:
JulijaS [17]2 years ago
3 0

The problem solved correctly as a single logarithm is log_{a} 2x^{3}/y^{2}

<h3>Simplifying Logarithm</h3>

From the question, we are to simplify the given logarithm

The given logarithm is

log_{a} 2x \ + \  2(log_{a} x -log_{a} y)

From the subtraction law of logarithm, we have that

log_{c} a -log_{c} b = log_{c} (a/b)

Thus,

The error in the solution was instead of multiplying, a was supposed to be divided by b

The correct solution is

log_{a} 2x \ + \  2(log_{a} x -log_{a} y)

log_{a} 2x \ + \  2(log_{a} (x/y) )

log_{a} 2x \ + \  log_{a} (x/y)^{2}

log_{a} 2x \ + \  log_{a} (x^{2}/y^{2})

Simplifying further

log_{a} 2x  \times (x^{2}/y^{2})

log_{a} 2x  \times x^{2}/y^{2}

log_{a} 2x^{3}/y^{2}

Hence, the problem solved correctly as a single logarithm is log_{a} 2x^{3}/y^{2}

Learn more on Simplifying logarithms here: brainly.com/question/247340

#SPJ1

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What is the slope of the line that contains the points (-4;2) and (6;-3) ?
tester [92]

Answer:

-1/2

Step-by-step explanation:

First you use to the formula m=y2-y1/x2-x1 and then you get -5/10 or -1/2. (m= slope)

4 0
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Graph the linear equation. Find three
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-3y = -2x -6

Y= 2/3x + 2


When x= 3
Y= 2/3(3) + 2
Y= 2+2 = 4

(3,4)


When x= 6
Y=2/3(6)+2
Y= 4+2 = 6

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When x= 12
Y= 2/3(12) + 2
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4 0
3 years ago
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Given the function, f(x)=√x-2 +3, choose the correct transformation.
prisoha [69]
Im only doing this for. Points so id say probably around at least 5
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2 years ago
Jan gives Ted a loan at 4% effective to be repaid by 10 annual payments of 100, followed by 5 annual payments of 200. Just after
olya-2409 [2.1K]

Answer:

139 ( D )

Step-by-step explanation:

Interest rate on loan = 4% = 0.04

Number of payments = 15

First 10 payments = 100 each

last 5 payments = 200 each

Calculating the value of K

K = [ ( 100 / 0.04 * ( 1-1 / 1.04^10 ) + 200/0.04 * ( 1-1 / (1 +0.04)^5)*  1 /1.04^10)

*  1.1 - 100 / 0.04 * ( 1-1 / (1+0.04)^5 ) - 200/0.04 * (1-1 /1.04^5) * 1/1.04^10)*0.04 / ( 1-1 / 1.04^5) * (1 + 0.04)^5

= 138.6051 ≈ 139

8 0
3 years ago
The perimeter of a quadrilateral (four-sides polygon) is 50 inches. The longest side is three times as long as the shortest side
kkurt [141]

The side lengths of quadrilateral are 21 inches; 11 inches; 11 inches; 7 inches.

<u>SOLUTION:</u>

Given, the perimeter of a quadrilateral (four-side polygon) is 50 inches.  

Let the length of shortest side be n inches.  The longest side is three times as long as the shortest side.  

That is, length of largest side = 3n inches

The other two sides are equally long and are 4 inches longer than the shortest side.  

Then, length of remaining two sides = 4 + n inches  

We have to find the length of all four sides.

Now, we know that, perimeter = 50 inches  

\begin{array}{l}{\rightarrow \text { Sum of all sides }=50} \\\\ {\rightarrow n+3 n+n+4+n+4=50} \\\\ {\rightarrow n+3 n+n+n=50-4-4} \\\\ {\rightarrow 6 n=42} \\\\ {\rightarrow n=7}\end{array}

So, length of sides will be,

7 \text { inches; } 3\times7=21 \text { inches; } 7+4=11 \text { inches; } 7+4=11 \text { inches. }

6 0
3 years ago
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