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Fudgin [204]
3 years ago
10

Central Middle School sold 50 tickets for one night of the school play. Student tickets sold for $2 each and adult tickets sold

for$3 each. They took in $135. How many of each type of ticket did they sell?
Mathematics
1 answer:
Andru [333]3 years ago
8 0
35 $3 tickets and 15 $2 tickets
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OverLord2011 [107]
The answer is 155 . 234-79=155 !
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karen was in a trivia contest and got 38 of the 40 questions correct. what precent of the questions did she get wrong?
iogann1982 [59]

Answer:

5 percent because it's percent is out of 100

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3 years ago
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If HJ=2x+5, JK=3x-7, and KH=18 what is the value of x
weqwewe [10]

Answer:

  • x = 4

Step-by-step explanation:

<u>Given</u>

  • HJ=2x+5
  • JK=3x-7
  • KH=18

<u>We see J is between H and K, so </u>

  • KH = HJ + JK
  • 2x + 5 + 3x - 7 = 18
  • 5x - 2 = 18
  • 5x = 20
  • x = 4

3 0
3 years ago
(X^2+x-6)(2x^2+4x) factor completely
MissTica

Answer:

2x\left(x-2\right)\left(x+3\right)\left(x+2\right)

Step-by-step explanation:

Lets go ahead and take a step by step approach to solving your problem.

First we must start by factoring x^2+x-6.

To do this, we must break the expression into groups! Although I will also provide a definition to help you understand! For ax^2+bx+c we need to find u, v > u\cdot \:v=a\cdot \:c and u+v=b which we will group into \left(ax^2+ux\right)+\left(vx+c\right).

The values we have are...a=1,\:b=1,\:c=-6 and u\cdot v=-6,\:u+v=1.

Now we need the factors of 6 which are 1, 2, 3 and 6. We also need the negative factors which you get simply by multiplying the positives by -1 or just reversing them.

Now we need to check for every two factors if u + v = 1.

\mathrm{Check}\:u=1,\:v=-6: \:u\cdot v=-6,\:u+v=-5 \Rightarrow  \mathrm{False}

\mathrm{Check}\:u=2,\:v=-3: \:u\cdot v=-6,\:u+v=-1 \Rightarrow  \mathrm{False}

\mathrm{Check}\:u=3,\:v=-2: \:u\cdot v=-6,\:u+v=1 \Rightarrow  \mathrm{True}

\mathrm{Check}\:u=6,\:v=-1: \:u\cdot v=-6,\:u+v=5 \Rightarrow  \mathrm{False}

Therefore u=3,\:v=-2.

Now we want to \mathrm{Group\:into\:}\left(ax^2+ux\right)+\left(vx+c\right). Which is \left(x^2-2x\right)+\left(3x-6\right).

Now we must factor x from x^2-2x.

Lets apply the exponent rule of a^{b+c}=a^ba^c which means x^2=xx.

Therefore we now have xx - 2x. Lets factor out the common term of x to get x(x - 2).

Now factor 3 out of 3x-6.

Rewrite 6 as 3 * 2. 3x-3\cdot \:2.

Now factor out the common term of 3 > 3\left(x-2\right).

x\left(x-2\right)+3\left(x-2\right) > Factor out the common term of x - 2 > \left(x-2\right)\left(x+3\right).

Now lets factor 2x^2+4x.

Apply the previous exponent rule of a^{b+c}=a^ba^c > x^2=xx > 2xx+4x.

Now rewrite 4 as 2 * 2 > 2xx+2\cdot \:2x.

Now factor out the common term of 2x to get 2x(x + 2).

Combine it all and we get 2x\left(x-2\right)\left(x+3\right)\left(x+2\right).

Hope this helps!

7 0
3 years ago
What is the missing length???​
Neporo4naja [7]

28 + 53 = 81.

180 - 81 = 99.

Your missing length is 99 degrees.

( Just remember that all triangles add up to 180 degrees )

If you need more help just message me

6 0
3 years ago
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