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denis-greek [22]
3 years ago
14

Please help me I will give you extra points and the brain thing (image below) 5/5

Mathematics
2 answers:
VMariaS [17]3 years ago
8 0
Your answer should be C.
Nesterboy [21]3 years ago
7 0
Your answer would be C
You might be interested in
Which set of fractions is ordered from least to greatest? 2/6,1/4,4/10 1/4,2/6,4/10 4/10,2/6,/14 or 1/4,4/10,2/6
oee [108]

Answer:

1/4, 2/6, 4/10

Step-by-step explanation:

1/4 = .25

2/6 = .333...

4/10 = .4

7 0
3 years ago
If integer k is equal to the sum of all even multiples of 15 between 295 and 615, what is the greatest prime factor of k?
ohaa [14]

Answer:

The greatest prime factor of k is 11.

Step-by-step explanation:

∵  LCM( 2, 15) = 30,

Thus, the even multiple of 15 must be multiple of 30,

That is, the even multiple of 15 between 295 and 615 are

300, 330, 360,..........600

Which is an AP,

Having first term, a = 300,

Common difference, d = 30,

If n be the number terms,

Last term = a+(n-1)d

=300+(n-1)30

=270 + 30n

\implies 270+30n = 600\implies 30n = 330\implies n = 11

Hence, the sum of the all even multiple of 15 from 295 to 615,

S_{11}=\frac{11}{2}(2(300)+(11-1)30)=\frac{11}{2}(600+300)=\frac{11}{2}(900)=11\times 450

According to the question,

S_{11}=k

⇒ k = 11 × 450 = 11 × 5 × 5 × 3 × 3 × 2

Hence, the greatest prime factor of k is 11.

3 0
3 years ago
The demand curve has what kind of sloping
GalinKa [24]
It usually slopes downward from left to right

3 0
3 years ago
Read 2 more answers
Which is a simplified form of the expression -9(y + 1) + 5y?
BabaBlast [244]
-9(y + 1) + 5y
Distribute the -9
-9y -9 + 5y
-4y -9
The answer is D
8 0
3 years ago
Read 2 more answers
Consider randomly selecting a student at a large university. Let A be the event that the selected student has a Visa card, let B
Tems11 [23]

Answer:

0.75

Step-by-step explanation:

Given,

P(A) = 0.6, P(B) = 0.4, P(C) = 0.2,

P(A ∩ B) = 0.3, P(A ∩ C) = 0.12, P(B ∩ C) = 0.1 and P(A ∩ B ∩ C) = 0.07,

Where,

A = event that the selected student has a Visa card,  

B = event that the selected student has a MasterCard,  

C = event that the selected student has an American Express card,

We know that,

P(A ∪ B ∪ C) = P(A) + P(B) + P(C) - P(A ∩ B) - P(A ∩ C) - P(B ∩ C) + P(A ∩ B ∩ C)

= 0.6 + 0.4 + 0.2 - 0.3 - 0.12 - 0.1 + 0.07

= 0.75

Hence, the probability that the selected student has at least one of the three types of cards is 0.75.

5 0
3 years ago
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