Healing was essential to the ministry of Jesus because He envisioned healing as a physical symbol of forgiveness. He guaranteed the ultimate glory of the human body through His personal resurrection, but forecast that restoration by healing twisted, shrunken, blinded limbs and organs. The paralytic's restoration is but one of many such examples (Mark 2:1-12).
Though there were many healers, Jesus was able to even raise up the dead, and also there was one instance where the Canaanite woman struggled through His disciples' desire to dismiss her, and His own initial, courteous refusal, to get what she knew she could trust Him to grant (Matthew 16:28). The crowds "begged him to let the sick just touch the edge of his cloak," (Matthew 14:36), for "all who touched him were healed."
Healers were not able to do that, and Jesus also claimed that he was God's son, so performing miracles like this was like proving the point. Also, healers were not always able to heal the person, but Jesus was able to do so all the time (for free even!) so many people traveled to meet him so he could heal them.
The woman with a hemorrhage crept silently through the crowd to merely touch His clothes (Mark 5:28). She also claimed that she went to many healers, but she didn't get healed, in fact, she got worse! So that's an instance that proves the point.
<em>Thank you :D</em>
To solve for the confidence interval for the population
mean mu, we can use the formula:
Confidence interval = x ± z * s / sqrt (n)
where x is the sample mean, s is the standard deviation,
and n is the sample size
At 95% confidence level, the value of z is equivalent to:
z = 1.96
Therefore substituting the given values into the
equation:
Confidence interval = 3 ± 1.96 * 5.8 / sqrt (51)
Confidence interval = 3 ± 1.59
Confidence interval = 1.41, 4.59
Therefore the population mean mu has an approximate range
or confidence interval from 1.41 kg to 4.59 kg.
Problem One
Call the radius of the second can = r
Call the height of the second can = h
Then the radius of the first can = 1/3 r
The height of the first can = 3*h
A1 / A2 = (2*pi*(1/3r)*(3h)] / [2*pi * r * h]
Here's what will cancel. The twos on the right will cancel. The 3 and 1/3 will multiply to one. The 2 r's will cancel. The h's will cancel. Finally, the pis will cancel
Result A1 / A2 = 1/1
The labels will be shaped differently, but they will occupy the same area.
Problem Two
It seems like the writer of the problem put some lids on the new solid that were not implied by the question.
If I understand the problem correctly, looking at it from the top you are sweeping out a circle for the lid on top and bottom, plus the center core of the cylinder.
One lid would be pi r^2 = pi w^2 and so 2 of them would be 2 pi w^2
The region between the lids would be 2 pi r h for the surface area which is 2pi w h
Put the 2 regions together and you get
Area = 2 pi w^2 + 2 pi w h
Answer: Upper left corner <<<<< Answer
